Remove URL parameters JS ES6 [duplicate]

Question

I have a url that contains a parameter, which I want to remove. I have created an if...else condition, but I would like to improve it in ES6.

if ( window.location.search.indexOf('&submit')  > -1 ) {
    window.location = urlBase + '/' + window.location.search;
} else {
    window.location = urlBase + '/' + window.location.search + '&submit=1';
}

Thank you in advance.

What would you hope that ES6 could improve in this code?

nils
– nils

2017-03-30 14:09:58 +00:00
Commented Mar 30, 2017 at 14:09 — nils
– nils, Commented Mar 30, 2017 at 14:09
I want just know if possible to reduce this condition.

Kevin Py
– Kevin Py

2017-03-30 14:10:49 +00:00
Commented Mar 30, 2017 at 14:10 — Kevin Py
– Kevin Py, Commented Mar 30, 2017 at 14:10

Randy · Accepted Answer · 2017-03-30 14:10:17Z

3

Not sure what your goal is, but here I've simply used includes and template literals.

if (window.location.search.includes('&submit')) {
    window.location = `${urlBase}/${window.location.search}`;
} else {
    window.location = `${urlBase}/${window.location.search}&submit=1`;
}

answered Mar 30, 2017 at 14:10

Randy

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