PHP image upload

Question

I am trying to upload an image to server using PHP and save inside a dir, and then returning the image url.

html code:

 <form method="post">
  <fieldset>
    <div class="form-group col-md-6 col-lg-6 col-sm-12">
       <input type="file" class="form-control" name="image" required="required">
    </div>
    <div class="form-group">
       <button type="submit" name="Save" class="btn btn-primary">Create</button>
    </div>
  </fieldset>
</form>

PHP code for upload image:

<?php
    if(isset($_POST['Save']))
    {
     /*image */
     $traget_dir="image/";
     $traget_file=$traget_dir .basename($_FILES["image"]["name"]);
     $uploadOk=1;
     $imageFileType = pathinfo($traget_file,PATHINFO_EXTENSION);
     $check=getimagesize($_FILES["image"]["tmp_name"]);
     if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
     } else{
        echo "File is not an image.";
       $uploadOk = 0;
     }
     /*end image upload*/
    }
    ?>

error on upload time:

Notice: Undefined index: image in

second error->

Warning: getimagesize() [function.getimagesize]: Filename cannot be empty in

thank for help and view.

can you show your full php code and html?

Adhan Timothy Younes
– Adhan Timothy Younes

2017-03-18 06:26:58 +00:00
Commented Mar 18, 2017 at 6:26 — Adhan Timothy Younes
– Adhan Timothy Younes, Commented Mar 18, 2017 at 6:26

Ankit Singh · Accepted Answer · 2017-03-18 06:31:16Z

2

Do this action after submit and check with if condition like following code. where 'SUBMIT' is the name of your button.

if(isset($_POST['SUBMIT']))
{
 /*image */
 $traget_dir="image/";
 $traget_file=$traget_dir .basename($_FILES["image"]["name"]);
 $uploadOk=1;
 $imageFileType = pathinfo($traget_file,PATHINFO_EXTENSION);
 $check=getimagesize($_FILES["image"]["tmp_name"]);
 if($check !== false) {
    echo "File is an image - " . $check["mime"] . ".";
    $uploadOk = 1;
 } else{
    echo "File is not an image.";
   $uploadOk = 0;
 }
 /*end image upload*/
}

answered Mar 18, 2017 at 6:31

Ankit Singh

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2 Comments

Ankit Singh Over a year ago

You've to add this in your form enctype="multipart/form-data"

Ankit Singh Over a year ago

like <form method="post" enctype="multipart/form-data">

Moustafa Elkady · Accepted Answer · 2017-03-18 09:18:40Z

1

For security reasons you have to check mime-type and extension also, and the best practice is to upload your files in /year/month/file to avoid file system problems, take a look at this code https://github.com/MoustafaElkady/SimpleUploader

answered Mar 18, 2017 at 9:18

Moustafa Elkady

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Comments

Ikhlak S. · Accepted Answer · 2017-03-18 10:22:59Z

0

You need to tell the form that its also going to be uploading files.

You can do this by using enctype=multipart/form-data

So, your form should look like:

<form method="post" enctype="multipart/form-data">
  <fieldset>
    <div class="form-group col-md-6 col-lg-6 col-sm-12">
       <input type="file" class="form-control" name="image" required="required">
    </div>
    <div class="form-group">
       <button type="submit" name="Save" class="btn btn-primary">Create</button>
    </div>
  </fieldset>
</form>

answered Mar 18, 2017 at 10:22

Ikhlak S.

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Comments

user7361089 · Accepted Answer · 2017-03-18 10:29:02Z

0

Replace this `

<form method="post">

with this

<form method="post" enctype="multipart/form-data">

and you are all good to go :)

answered Mar 18, 2017 at 10:29

user7361089

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