Get object keys with the highest value in Javascript

Question

Imagine an object like this:

var values = {
    "2": 1,
    "53": 2,
    "56": 4,
    "57": 9,
    "61": 2,
    "62": 16,
    "63": 2,
    "398": 24,
    ...
}

My goal is, to find the 10 object keys, which have the highest value. In this case: 398, then 62 and so on (= [398, 62, ...]). I know how I can put this into an array, don't know how to receive the property key though.

Important: I can't change the format because it's a server response.

I tried with a for (key in values) {} loop but have no idea how to move on. This similar question and it's answer couldn't really help me either.

Create array of keys and then sort descending based on value and get first 10 — Rajesh Dixit
– Rajesh Dixit, Commented Mar 10, 2017 at 11:34

Rajesh Dixit · Accepted Answer · 2017-03-10 11:42:17Z

7

As commented before:

Create an array of keys: Object.keys(object)
Sort this array based on value: sort((a,b)=> object[b] - object[a])
Get necessary values: keys.slice(0,n)

var value = {2:1,53:2,56:4,57:9,61:2,62:16,63:2,398:24};

function getKeysWithHighestValue(o, n){
  var keys = Object.keys(o);
  keys.sort(function(a,b){
    return o[b] - o[a];
  })
  console.log(keys);
  return keys.slice(0,n);
}

console.log(getKeysWithHighestValue(value, 4))

answered Mar 10, 2017 at 11:42

Rajesh Dixit

25k5 gold badges52 silver badges86 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Nina Scholz · Accepted Answer · 2017-03-10 11:39:23Z

3

You could sort by the values property and slice the result.

var values = { 2: 1, 53: 2, 56: 4, 57: 9, 61: 2, 62: 16, 63: 2, 398: 24 },
    result = Object
        .keys(values)
        .sort(function (a, b) { return values[b] - values[a]; })
        .slice(0, 10)
        .map(Number);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Mar 10, 2017 at 11:39

Nina Scholz

388k26 gold badges367 silver badges417 bronze badges

Comments

Vikramaditya · Accepted Answer · 2017-03-10 11:36:21Z

1

You can use Object.keys to get key values

var value = {
"2": 1,
"53": 2,
"56": 4,
"57": 9,
"61": 2,
"62": 16,
"63": 2,
"398": 24,
}
var parsedKeys = Object.keys(value).map(x => parseInt(x));
var sortedKeys = parsedKeys.sort(function (a, b) {  return b - a;  });

Now you can get highest top 10 keys by sortedKeys.slice(0, 10);

answered Mar 10, 2017 at 11:36

Vikramaditya

5,5947 gold badges37 silver badges47 bronze badges

2 Comments

NoobCoder Over a year ago

What if I have array of words with count ? ex:- [ { "text":"hello", "size":10},{ "text":"world", "size":2} ,....] same to 100 object and find top 10 text and store it in an array ?

Vikramaditya Over a year ago

See the example given here

Đào Minh Hạt · Accepted Answer · 2017-03-10 11:37:54Z

-1

var value = {
    "2": 1,
    "53": 2,
    "56": 4,
    "57": 9,
    "61": 2,
    "62": 16,
    "63": 2,
    "398": 24
};

var sortable = [];
for (var key in value) {
    sortable.push([key, value[key]]);
}

sortable.sort(function(a, b) {
    return b[1] - a[1];
});

var result = [];
sortable.forEach(function(a) {
  result.push(a[0]);
});

console.log(result.slice(0, 10));

answered Mar 10, 2017 at 11:37

Đào Minh Hạt

2,92618 silver badges20 bronze badges

Collectives™ on Stack Overflow

Get object keys with the highest value in Javascript

4 Answers 4

Comments

Comments

2 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related