Javascript: How can I return console.log result into string form?

Question

As title, I am getting the result that I wanted from console.log(result), however, how can I pass this console.log result to the string variable and "return" it? I am having trouble returning the result of console.log(). Thanks!

var type = ["men","women","boys", "girls"]
var product = "women shoes";
product.split(' ').forEach(function(item){
    type.forEach(function(elem){
      if(elem==item){
        console.log(elem);
      }
    });
});

Thank you for all the answers here, and it is so amazing that so many people are willing to help my beginner problem. Let me clear my question a little bit here, like above, console.log (elem) will return woman, however, if i replace the line concole.log(elem) with return(elem) will get me nothing. Why is that?

why don't you just return the result variable in your console.log() ? — Nicolas
– Nicolas, Commented Feb 16, 2017 at 16:49
I don't understand. console.log will just print whatever value you pass it to the console. That same value is still available. Could you please create a MCVE to show us your problem? — Mike Cluck
– Mike Cluck, Commented Feb 16, 2017 at 16:49
Do you want to convert result to a string? Then JSON.stringify is your friend: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Patrick Hund
– Patrick Hund, Commented Feb 16, 2017 at 16:51
As @PatrickHund said, if you are logging and array and you want to get the string of the array you should consider using JSON.stringify() but once again, this question lack a lot of information. — Nicolas
– Nicolas, Commented Feb 16, 2017 at 16:53

Kalman · Accepted Answer · 2017-02-16 16:53:24Z

3

console.log formats whatever you pass inside to a string and outputs it. You can do the same, by explicitly calling toString() as follows:

console.log(result);

return result.toString();

As mentioned in the comments by @Patrick Hund, if result is a Javascript object, you can use JSON.stringify to convert it to a string (and then return it) as follows:

return JSON.stringify(result, null, 2);

answered Feb 16, 2017 at 16:53

Kalman

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1 Comment

angrykoala Over a year ago

This is not completely correct. As described here: stackoverflow.com/questions/28397861/… the behaviour for Node.js may be different

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