I'm following a react tutorial but I'm lost. I don't understand starting line 9.
so I tried to make a little miarature
const updateTodo = (list, updated) => {
const index = list.findIndex(item => item.id === updated.id)
return [
...list.slice(0,index),
updated,
...list.slice(index+1)
]
}
https://jsbin.com/sifihocija/2/edit?js,console but failed to produce the result that the author did, what's wrong?
Issue is in this line:
const index = list.findIndex(item => item.id === updated.id)
updated is an array, to access the id, you need to specify the index also,
for other array you are using loop, so item will be the each object of the array, and item.id will give you the id of each object, try this:
const index = list.findIndex(item => item.id === updated[0].id)
const arr = [
{id:1,name:'hello'},
{id:2,name:'hai'}
]
const arr2 = [
{id:2,name:'this should be a new string'}
]
const updateTodo = (list, updated) => {
const index = list.findIndex(item => item.id === updated[0].id);
return [
...list.slice(0,index),
...updated,
...list.slice(index+1)
]
}
console.log(JSON.stringify(updateTodo(arr,arr2)))Check the working code: https://jsbin.com/pazakujava/edit?js,console
Let me know if you need any help in this.
const arr2 = {id:2,name:'this should be a new string'} you can try this arr2, ur code will also work :)It's simpler and cleaner using Array.map:
const updateTodo = (list, updated) =>
list.map((item) => {
if (item.id !== updated.id) {
return item;
}
return updated;
});
For some reason the updated argument is an array, and therefore updated.id wont work. In that case, if you want to update the list item with that id the cleanest way to update list without mutating it would be to use Array.prototype.with() :
const updateTodo = (list, updated) => {
const index = list.findIndex(item => item.id === updated[0].id);
return list.with(index, updated[0]);
}
