Implode array using two array_column

Question

I have a result from a query like this : (IN PHP, I assigned to $arr_permasalahan)

+--------------+---------------------+
| total_detail | nama_detail         |
+--------------+---------------------+
|            2 | Create Email Baru   |
|            1 | Create Login Novell |
+--------------+---------------------+

Now I want to implode them, like this :

Create Email Baru  : 2 pcs,
Create Login Novel : 1 pcs

So, I decided it to use array_column like this :

 $output =  implode("\n", array_column($arr_permasalahan, 'nama_detail'));

I just get

"Create Email Baru\nCreate Login Novell"

Please advise.

You can do it in the query only - CONCAT(nama_detail, ' : ', total_detail, ' pcs') and then print it as you need. — Sougata Bose
– Sougata Bose, Commented Feb 1, 2017 at 6:22

Prudhvi Raj Kumar · Accepted Answer · 2017-02-01 06:13:57Z

2

Try to use like this, it may help..! I think there is not need to use implode in this

     $line = "";
     foreach($arr_permasalahan as $line)
     echo "".$line[' nama_detail']." : ".$line['total_detail']." pcs";

answered Feb 1, 2017 at 6:13

Prudhvi Raj Kumar

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2 Comments

Fadly Dzil Over a year ago

I have tried this way, it success, but too oldiest style.

mickmackusa Over a year ago

There is no benefit in prepending an empty string to the other data.

Suchit kumar · Accepted Answer · 2017-02-01 06:29:39Z

1

you can try this:

$elemet=implode("<br>",array_map(function($x){
    return $x['nama_detail'].":".$x['total_detail']." pcs";
},$arr_permasalahan));
echo $elemet;

NOTE: what @Sougata Bose suggested in comment will be the best option.

answered Feb 1, 2017 at 6:29

Suchit kumar

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Comments

Krishna Gupta · Accepted Answer · 2017-02-01 06:49:58Z

1

You can impload array values using impload()

Below mrentioned code will be full fill your requirement

$arr = array(1 => array('total_detail' => 2, 'nama_detail' => 'Create Email Baru'), 2 => array('total_detail' => 1, 'nama_detail' => 'Create Login Novell'));

  foreach ($arr as $i => $v) {
    $ss['nama_detail'] = $v['nama_detail'];
    $ss['total_detail'] = $v['total_detail'].' pcs';
    echo implode("':'",$ss)."' pcs<br>";
  }

Actually your result array is multi level array (2d-array) and impload() works for single level array so you must need to put a foreach loop. See your required result here

answered Feb 1, 2017 at 6:49

Krishna Gupta

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Comments

B. Desai · Accepted Answer · 2022-08-01 08:07:56Z

1

Try this solution

foreach($arr_permasalahan as $permasalahan)    
{
      echo $permasalahan['nama_detail']." : ".$permasalahan['total_detail']." pcs"."<br>";     
}

edited Aug 1, 2022 at 8:07

answered Feb 1, 2017 at 6:20

B. Desai

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