Mapping an arrays values to another array

Question

I have this 2d array called input and I am trying to map different numbers in another array to change it. In the 2d array mapping it contains all the mappings I want to perform.The first array is {0,2,3,4,1,5} and I want to use this to change the values in input so every 1 becomes a 2, and 2 to 3 and 3 to 4 and 4 to 1. I have 23 different mappings in that mapping array which I would want to change the values of input. Here is what I have tried so far.

 public static int [][] mapOrientation(int input[][]){
    int [][] input = {{0,0,0,5},{4,1,1,4},{2,2,0,2},{1,2,3,5},{3,3,3,4},{1,5,5,4}};

     int[][] mapping ={{0,2,3,4,1,5},{1,2,0,4,5,3},{5,2,1,4,3,0},{3,2,5,4,0,1},
                       {3,5,4,0,2,1},{2,5,3,0,1,4},{1,5,2,0,4,3},{4,5,1,0,3,2},
                       {4,1,0,3,5,2},{5,1,4,3,2,0},{2,1,5,3,0,4},{0,1,2,3,4,5},
                       {0,4,1,2,3,5},{3,4,0,2,5,1},{5,4,3,2,1,0},{1,4,5,2,0,3},
                       {1,0,4,5,2,3},{2,0,1,5,3,4},{3,0,2,5,4,1},{4,0,3,5,1,2},
                       {4,1,0,3,5,2},{5,1,4,3,2,0},{2,1,5,3,0,4}};

    int [] comb = mapping[0];
    for(int i = 0; i < input.length; i++){
        for(int j = 0; j < input[i].length; j++){

            input[i][j] = comb[0];
            System.out.println(comb[0]);
            System.out.println(Arrays.deepToString(input));

   cubeToString = Arrays.deepToString(input);

    return input;
}

If this is still unclear my goal is to change input from

int [][] input ={{5,1,2,0},{2,0,1,4},{1,2,5,5},{3,0,1,3},{4,3,0,4},{3,2,5,4}}

to:

int [][] input ={{5,2,3,0},{3,0,2,1},{2,3,5,5},{4,0,2,4},{1,4,0,1},{4,3,5,1}}

This would be the result I want using comb[0].

why are the mapping arrays bigger than the input arrays? i'm confused... is the result you want based on using the mapping[0][0] on input and the result would be in comb[0]? — RAZ_Muh_Taz
– RAZ_Muh_Taz, Commented Jan 11, 2017 at 17:14
because the mapping arrays contain the combination of mappings of which I would like to use to modify input so I use comb[0] to access the first mapping array @RAZ_Muh_Taz — cuber
– cuber, Commented Jan 11, 2017 at 17:17
What do you mean by the mapping arrays contain the combination of mappings? how does it work ? — Null
– Null, Commented Jan 11, 2017 at 17:19
No 0 -> 0, 1-> 2, 2 -> 3, 3 -> 4, 4 -> 1 is the first combination. @Michael — cuber
– cuber, Commented Jan 11, 2017 at 17:22
Is the number of inputs aqual to the number of the mappings or you just want to implement one mapping to all the inputs? — user3408531
– user3408531, Commented Jan 11, 2017 at 17:22

Michael · Accepted Answer · 2017-01-11 18:09:28Z

1

Your problem is with this line:

 input[i][j] = comb[0];

You are setting the value to always equal the first item of the mapping. What you actually want is

 input[i][j] = comb[input[i][j]];

Runnable example

public class NewClass
{
    public static void main(String... args)
    {
        int[][] input = {{5,1,2,0},{2,0,1,4},{1,2,5,5},{3,0,1,3},{4,3,0,4},{3,2,5,4}};
        mapOrientation(input);
    }

    public static int [][] mapOrientation(int input[][])
    {
        int[][] mappings ={{0,2,3,4,1,5},{1,2,0,4,5,3},{5,2,1,4,3,0},{3,2,5,4,0,1},
                           {3,5,4,0,2,1},{2,5,3,0,1,4},{1,5,2,0,4,3},{4,5,1,0,3,2},
                           {4,1,0,3,5,2},{5,1,4,3,2,0},{2,1,5,3,0,4},{0,1,2,3,4,5},
                           {0,4,1,2,3,5},{3,4,0,2,5,1},{5,4,3,2,1,0},{1,4,5,2,0,3},
                           {1,0,4,5,2,3},{2,0,1,5,3,4},{3,0,2,5,4,1},{4,0,3,5,1,2},
                           {4,1,0,3,5,2},{5,1,4,3,2,0},{2,1,5,3,0,4}};

        System.out.println("Before");
        System.out.println(Arrays.deepToString(input));

        int[] mapping = mappings[0];
        for(int i = 0; i < input.length; i++)
        {
            for(int j = 0; j < input[i].length; j++)
            {
                input[i][j] = mapping[input[i][j]];
            }
        }

        System.out.println("After");
        System.out.println(Arrays.deepToString(input));

        //cubeToString = Arrays.deepToString(input);

        return input;
    }
}

edited Jan 11, 2017 at 18:09

answered Jan 11, 2017 at 17:36

Michael

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2 Comments

cuber Over a year ago

I did try doing that as well but it wouldn't change the values of input.

Michael Over a year ago

I've tested it and it matches your expected results. I've edited in a runnable example to my answer.

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