How to echo all values from array in bash

Question

I am making a bash script using dialog. My script make the difference between files in two tar.gz. Each add files are put in an array and each delete files are put in an other array.

All files are add in my two array and when I want echo them it's works

echo ${tabAjout[@]}
echo ${tabSuppr[@]}

The output is :

bonjour.txt.gpg test2.txt.gpg test.txt.gpg
hello.txt.gpg

Now I want add this in msgbox.

function affiche_message(){
    #Personnalisation de la fenêtre
    $DIALOG --title "$1" \
            --msgbox "$2" 20 45
}

Call function :

affiche_message "Title" "Delete : ${tabSuppr[@]} \n\n Add : ${tabAjout[@]}"

When I run my script the msgbox contains only the first values of the array. If I change ${tabAjout[@]} by ${#tabAjout[@]} the dialog windows echo that array contains 3 values.

choroba · Accepted Answer · 2025-11-17 21:52:01Z

130

Use * as the subscript to expand the array as a single word with the values of each element separated by the first character of the IFS special variable:

"${tabSuppr[*]}"

See man bash for explanation.

edited Nov 17 at 21:52

answered Dec 14, 2016 at 19:45

choroba

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6 Comments

zundi Over a year ago

Any way to get each item on its own line?

choroba Over a year ago

@zundi: The following seems to work:

( IFS=$'%'; ajout="${tabAjout[*]}"; suppr="${tabSuppr[*]}" ; affiche_message "Title" "Delete : ${suppr//%/\\n}\n\nAdd : ${ajout//%/\\n}" ; )

.

elad silver Over a year ago

You got my upvote for the answer but "See man bash for explanation." not very usefull at all... can anyone explain this?

choroba Over a year ago

@eladsilver: When you use * as an array index in double quotes, bash expands the array as a single word, separating the elements by the first character of the special variable $IFS.

Loye Young Jun 3 at 18:47

@zundi "Any way to get each item on its own line?" echo "${tabSuppr[*]}" | sed 's| |\n|g'

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