0

I have the following array:

a = np.array([[0,1,2,3,4,5,6,7],[8,9,10,11,12,13,14,15],[16,17,18,19,20,21,22,23],[24,25,26,27,28,29,30,31],[32,33,34,35,36,37,38,39,],[40,41,42,43,44,45,46,47],[48,49,50,51,52,53,54,55],[56,57,58,59,60,61,62,63]])

How can I write a function that takes a number 0-63 as input, and tells me where that number is in the array?

example: function(0) returns a[0,0]; function(13) returns a[5,1]

Improve this question
3
  • 1
    Of course, this is possible. Commented Dec 3, 2016 at 17:13
  • @ForceBru I changed the wording. I assumed it's possible, I just have no idea how to do it. Commented Dec 3, 2016 at 17:24
  • See stackoverflow.com/questions/40949132/… Commented Dec 3, 2016 at 17:25

1 Answer 1

Reset to default
4

The shortest way (gives you the indices in oposite order) is

np.argwhere(a==13)

gives: 

array([[1, 5]])
Improve this answer
Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.