Find an entire object in array of objects

Question

How do I find Array2 in Array1 . I have been using $.inArray() method or indexOf() but it return false yet the statement is true.

var array1 = [{
    h: 1480508328,
    rid: 16,
    sid: 2
  }, {
    h: 87542,
    rid: 18,
    sid: 9
  }
];
var array2 = {
  h: 1480508328,
  rid: 16,
  sid: 2
};
//test if array2 exist in array1
if ($.inArray(array2, array1) > 0) {
  console.log('Object is in array');
} else {
  console.log('Object is not in array');
}

Please help. Thank you

FYI, array2 is not an array. It's an object. array2 is also not in array1, only an object which looks like array2. So you'll have to iterate over array1 and check if any item matches array2. — Mike Cluck
– Mike Cluck, Commented Nov 30, 2016 at 16:25
but var array1 is an associative array (value pare) .... isn't it? — james Oduro
– james Oduro, Commented Nov 30, 2016 at 16:32
well.... no. To quote: "JavaScript does not support arrays with named indexes. In JavaScript, arrays always use numbered indexes. "* — yuvi
– yuvi, Commented Nov 30, 2016 at 16:34
@jamesOduro In a way you could say that but we don't call them associative arrays in JS since there's no guarantees on order. They're called objects. — Mike Cluck
– Mike Cluck, Commented Nov 30, 2016 at 16:36

Nina Scholz · Accepted Answer · 2016-12-01 07:20:50Z

4

You could iterate the array and check the length of the properties with the length of the given object and check every value.

var array = [{ h: 1480508328, rid: 16, sid: 2 }, { h: 87542, rid: 18, sid: 9 }],
    object = { h: 1480508328, rid: 16, sid: 2 },
    found = array.some(function (a) {
        var keys = Object.keys(a);
        return keys.length === Object.keys(object).length && keys.every(function (k) {
            return a[k] === object[k];
        });
    });
  
console.log(found);

var array = [{ h: 87542, rid: 18, sid: 9 }, { h: 1480508328, rid: 16, sid: 2 }],
    object = { h: 1480508328, rid: 16, sid: 2 },
    found = array.some(function (a) {
        var keys = Object.keys(a);
        return keys.length === Object.keys(object).length && keys.every(function (k) {
            return a[k] === object[k];
        });
    });
  
console.log(found);

edited Dec 1, 2016 at 7:20

answered Nov 30, 2016 at 16:34

Nina Scholz

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4 Comments

james Oduro Over a year ago

I think your answer is the best solution

james Oduro Over a year ago

The answer yuvi provided has a big problem if the sorting is not the same.. An element could be found at position 1 and not in position 0

james Oduro Over a year ago

So how do I return the position of the item found ?

Nina Scholz Over a year ago

@jamesOduro, it does not matter, because all elements of the array are checked. please see edit with reversed items.

kukkuz · Accepted Answer · 2016-11-30 16:38:59Z

3

Use Array.prototype.every to check if each object property of the array and the object matches - now use Array.prototype.some to check if at least once the object exists inside the array.

See demo below:

var array1=[{h:1480508328,rid:16,sid:2},{h:87542,rid:18,sid:9}];
var object={h:1480508328,rid:16,sid:2}

var result = array1.some(function(e){
  return Object.keys(object).length === Object.keys(e).length && Object.keys(e).every(function(k){
    return k in object && e[k] === object[k];
  });
});

console.log(result);

edited Nov 30, 2016 at 16:38

answered Nov 30, 2016 at 16:33

kukkuz

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3 Comments

james Oduro Over a year ago

what is the object property...do you mean the 'key'??

kukkuz Over a year ago

object is the same as your array2

Redu Over a year ago

@james Oduro Objects have properties and arrays have keys which are also properties since an array is an object in JS. Yet arrays may also have properties which are not keys. It's best to think it like that.

yuvi · Accepted Answer · 2016-11-30 16:29:35Z

1

You can stringify it and check for equality

var array1 = [{
    h: 1480508328,
    rid: 16,
    sid: 2
  }, {
    h: 87542,
    rid: 18,
    sid: 9
  }
];
var array2 = {
  h: 1480508328,
  rid: 16,
  sid: 2
};

var dat1 = JSON.stringify(array2);
array1.forEach(function(item){
    if(JSON.stringify(item) === dat1){
        console.log(dat1)
    } else {
        console.log('Not match')
    }
});

JSFIDDLE

edited Nov 30, 2016 at 16:29

yuvi

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answered Nov 30, 2016 at 16:27

brk

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3 Comments

Leonardo Lana Over a year ago

Note: It might be a problem if object's attributes are differently sorted.

james Oduro Over a year ago

for some reason to help my project I choose yours as the answer

james Oduro Over a year ago

Thank you so much.

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