How to convert string into list of array

Question

I have written code to generate all the dates for the given month:

nb_days = monthrange(2016, 2)[1]
dateDict = [datetime.date(year, month, day) for day in range(1, nb_days+1)]
outputItems = []
for dd in dateDict:
    outputItems.append(dd.strftime('%Y-%m-%d'))

My output is something like this:

['2016-02-01', '2016-02-02', '2016-02-03', '2016-02-04', '2016-02-05', '2016-02-06', '2016-02-07', '2016-02-08', '2016-02-09', '2016-02-10', '2016-02-11', '2016-02-12', '2016-02-13', '2016-02-14', '2016-02-15', '2016-02-16', '2016-02-17', '2016-02-18', '2016-02-19', '2016-02-20', '2016-02-21', '2016-02-22', '2016-02-23', '2016-02-24', '2016-02-25', '2016-02-26', '2016-02-27', '2016-02-28', '2016-02-29']

I need get result something like:

[('2016-02-01', '0', '0', '0'), ('2016-02-02', '0', '0', '0'), ('2016-02-03', '0', '0', '0'), ('2016-02-04', '0', '0', '0'), .....]

You could try something like this, outputItems.append(((dd.strftime('%Y-%m-%d'),)),) I don't understand what are '0's in ('2016-02-01', '0', '0', '0') Its upto you how you add them. — Jaimin Ajmeri
– Jaimin Ajmeri, Commented Nov 28, 2016 at 5:34

Jaimin Ajmeri · Accepted Answer · 2016-11-28 05:47:38Z

1

Try this outputItems.append( (dd.strftime('%Y-%m-%d'), '0', '0', '0') )

nb_days = monthrange(2016, 2)[1]
dateDict = [datetime.date(year, month, day) for day in range(1, nb_days+1)]
outputItems = []
for dd in dateDict:
    outputItems.append( (dd.strftime('%Y-%m-%d'), '0', '0', '0') )

answered Nov 28, 2016 at 5:47

Jaimin Ajmeri

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