difference of two sets (lists) in python

Question

stb_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
passive_boxes_list = []
active_boxes_list = set(stb_list) - set(passive_boxes_list)
print active_boxes_list

I have got two lists. The number is going to be added into the passive_boxes_list dynamically (1-16).

How I can subtract stb_list from passive_box_list.

For example: if passive_boxes_list = [1 , 2 , 3] then active_box_list should be:

active_boxes_list = [4, 5,6, 7, 8, 9, 10, 11, 12, 13,14,15,16]

Are you after some kind of view which updates each time passive_boxes_list dynamically updates? — doctorlove
– doctorlove, Commented Nov 21, 2016 at 15:06
Your code already works, doesn't it? (Although you could potentially convert active_boxes_list to a list from a set.) Can you be more specific about what behaviour you want? If you want something that really updates dynamically, you're going to have to build a function or a class. (Also, I think the name operation is just "difference", not "distraction", in English) — Andrew Jaffe
– Andrew Jaffe, Commented Nov 21, 2016 at 15:25
One possibility that is about as terse as any other that doesn't involve a non-pythonic amount of reliance on globals or other magic: active_boxes_list -= set(passive_boxes_list) — Andrew Jaffe
– Andrew Jaffe, Commented Nov 21, 2016 at 15:39
perhaps this is better as a class to encapsulate the moving of number between estates and so you can easily update both when a new active or passive is added — Copperfield
– Copperfield, Commented Nov 21, 2016 at 15:39

Thomas Blanquet · Accepted Answer · 2016-11-21 15:11:51Z

3

You should use the List Comprehension feature.
So you should have something like active_boxes_list = [x for x in stb_list if x not in passive_list]
Hope this help !

answered Nov 21, 2016 at 15:11

Thomas Blanquet

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1 Comment

Andrew Jaffe Over a year ago

The OP's set commands already do this part of the job (more elegantly)!

Jaroslaw Matlak · Accepted Answer · 2016-11-21 15:08:54Z

-1

You can try this:

list = [1,2,3,4,5,6,7]
bleh=[1,2,3,10]
for x in bleh:
    if x in list:
        del list[list.index(x)]
print list

answered Nov 21, 2016 at 15:08

Jaroslaw Matlak

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