jquery: determine if a string contains characters of an array

Question

i'm having the following code:

var specialchars = [246,214,228,196,252,220,223]; // holds german umlauts + ß
var foo = "abcdefä41hl";

what's the best practise for detecting if foo contains a character's ascii-code from the array? in that case it would return true as it contains "ä" (ascii code 228).

thanks

JavaScript uses the UTF-16 encoding of Unicode, not ASCII. So ß, for example, is better written as "ß" or "\u00df". (ß isn't even an ASCII character.) So, why not make specialchars an array of strings? — Tom Blodget
– Tom Blodget, Commented Nov 11, 2016 at 3:24

Rajaprabhu Aravindasamy · Accepted Answer · 2016-11-10 15:43:35Z

1

You can detect that by,

var specialchars = [246,214,228,196,252,220,223];
var foo = "abcdefä41hl";
var isExist = !!([...foo].find(itm => specialchars.includes(itm.charCodeAt())));

console.log(isExist); // true

Or you could use Array.prototype.some instead of find as suggested in the comment,

var isExist = [...foo].some(itm => specialchars.includes(itm.charCodeAt()));

edited Nov 10, 2016 at 15:43

answered Nov 10, 2016 at 15:35

Rajaprabhu Aravindasamy

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5 Comments

castletheperson Over a year ago

You might want Array#some instead of find, so that it returns a boolean.

Rajaprabhu Aravindasamy Over a year ago

@4castle Updated! Thanks for the heads up.

Fuxi Over a year ago

sorry to bother you but is [...foo] the correct syntax? it's not working .. :/ would you please update the solution?

Rajaprabhu Aravindasamy Over a year ago

@Fuxi Nothing is gonna bother me. :-) Are you using ES6? That one is called as spread operator.

castletheperson Over a year ago

@Fuxi If [...foo] isn't working, you can also do foo.split('') for that part.

fafl · Accepted Answer · 2016-11-10 15:35:48Z

0

Quite easily:

foo.split("").filter(c => specialchars.indexOf(c.charCodeAt()) != -1).length != 0

It splits the string to an array of chars, keeps only the ones that exist in the list of special characters and checks if any are left.

answered Nov 10, 2016 at 15:35

fafl

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