Parse error with PHP json_encode

Question

I'm getting an odd error and I'm not sure why it's happening. I'm trying to send multiple values to my ajax call which is resulting in undefined.

I tried to debug it and I realized that my PHP is getting a parse error with my json_encode. The reason seems to be with the passing of multiple values. Can anyone explain why is that so?

<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);

$files = glob("images/*.*");

for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];
}

echo json_encode("array_of_images" => $files, "size_of_array" => sizeof($files));
?>

Update: Ajax Code

<script>
    $.ajax({    //create an ajax request to load_page.php
        type: "GET",
        url: "img.php",             
        dataType: "html",   //expect html to be returned                
        success: function(response){     
            alert(response.array_of_images);
            alert(response.size_of_array);
        },
        error:function (xhr, ajaxOptions, thrownError){
           // alert(thrownError);
        }
    });
</script>

aynber · Accepted Answer · 2016-11-09 16:42:37Z

4

The second value passed to json_encode should be options, not more data. You need to make your parameters into an array instead of passing it as 2 values:

 echo json_encode(array("array_of_images" => $files, "size_of_array" => sizeof($files)));

answered Nov 9, 2016 at 16:42

aynber

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5 Comments

nTuply Over a year ago

Thanks, but why do I still get an undefined on the following ajax response: success: function(response){ alert(response.array_of_images); alert(response.size_of_array); },

aynber Over a year ago

Try console.log(response) before you alert it to find out what exactly it contains.

nTuply Over a year ago

Undefined in console.log as well. If I have only say json_encode($files) it works.

aynber Over a year ago

Response is undefined? You'd have to show your ajax code to see what's going on there.

aynber Over a year ago

Try changing your dataType to json.

Jose Rojas · Accepted Answer · 2016-11-09 16:42:29Z

2

Add header and json_encode receive as parameter an array so it would be like this:

header('Content-Type: application/json');
echo json_encode(["array_of_images" => $files, "size_of_array" => sizeof($files)]);

answered Nov 9, 2016 at 16:42

Jose Rojas

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Comments

Aniket Sahrawat · Accepted Answer · 2016-11-09 16:42:50Z

2

json_encode accepts array. So you must write it like

echo json_encode(array("array_of_images" => $files, "size_of_array" => sizeof($files)));

answered Nov 9, 2016 at 16:42

Aniket Sahrawat

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