Unable to pass struct array to function in C

Question

Learning C and need to populate array of five struct elements but I can't seem to figure out how to pass the struct array to a function and I keep getting error:

error: conflicting types for 'dealFiveHand'

Here is the code:

#define HAND_SIZE 5

void dealFiveHand(struct Card *wHand[]);

struct Card {
    char suit;
    char face;
};

int main(void)
{
    struct Card *hand[HAND_SIZE];
    dealFiveHand(hand); 
}

void dealFiveHand(struct Card *wHand[])
{
   ...
}

Do I need to define and initialize a pointer and then pass that pointer to the function?

Is that the complete error message? There's nothing else? No informational notes or anything else printed as part of the error? — Some programmer dude
– Some programmer dude, Commented Nov 6, 2016 at 4:49
Please show the full error message. Please show the exact code as a minimal reproducible example (what you have is close already so just make it the actual code with the actual error message including line numbers). — kaylum
– kaylum, Commented Nov 6, 2016 at 4:49

tdao · Accepted Answer · 2016-11-06 04:49:31Z

4

At least you need to move the definition of struct Card BEFORE function dealFiveHand prototype - that way the function knows about the type of its parameter.

struct Card {
    char suit;
    char face;
};

void dealFiveHand(struct Card *wHand[]);

answered Nov 6, 2016 at 4:49

tdao

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1 Comment

user2300867 Over a year ago

Thanks. Makes sense. Not sure how I was missing it.

Mangu Singh Rajpurohit · Accepted Answer · 2016-11-06 04:53:04Z

3

You are referring Card, before defining it. Declare it first, before referring it, as a argument of your function dealFiveHand()

answered Nov 6, 2016 at 4:53

Mangu Singh Rajpurohit

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