Input Function Within While Loop

Question

In this program I am attempting to have it so that the variable integer_enter within the while loop will keep being assigned integers until a 0 is entered in to the input. Every time I run the code I get an EOF error on the "integer_enter= int(input())" line. Why would that be? There is nothing wrong with defining a variable within a while loop so why am I getting that error?

Code for reference:

list_num = [ ]
count_even = 0

loop_condition= True

while(loop_condition == True):
    integer_enter= int(input())
    integer_append= list_num.append(integer_enter)
    if(integer_enter % 2 == 0):
        count_even += 1
    elif(integer_enter == 0):
        loop_condition = False 




print('The number of even integers is %d' % count_even)

print(list_num)

BTW, integer_append is None will always be true because list.append doesn't return anything. — Kirk Strauser
– Kirk Strauser, Commented Oct 26, 2016 at 4:00

Divyanshu Maithani · Accepted Answer · 2016-10-26 03:57:36Z

1

You need to modify your condition for the loop termination. You need to make sure that your if is not executed when the integer_enter is 0. This is a working link to your code.

list_num = [ ]
count_even = 0

loop_condition= True

while(loop_condition == True):
    integer_enter= int(input())
    integer_append= list_num.append(integer_enter)
    if(integer_enter % 2 == 0 and integer_enter != 0):
        count_even += 1
    elif(integer_enter == 0):
        loop_condition = False 




print('The number of even integers is %d' % count_even)

print(list_num)

answered Oct 26, 2016 at 3:57

Divyanshu Maithani

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1 Comment

Darien Springer Over a year ago

Thanks. I forgot that 0 % 2 would also equal 0.

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