Java - Creating a web browser

Question

I am creating a web browser in java and am receiving the following error when I attempt to run it:

Exception in thread "main" java.net.MalformedURLException: no protocol:

I have not been able to find an answer to my particular problem but I believe it has something to do with my socket. Do I simply need to add a MalformedURLException? Any help is appreciated.

import javax.swing.*;
import java.io.*;
import java.net.*;
import java.awt.*;
import java.awt.event.*;

public class Browser extends JFrame {

    public JPanel addressPanel, windowPanel;
    public JLabel addressLabel;
    public JTextField textField;
    public JEditorPane windowPane;
    public JScrollPane windowScroll;
    public JButton addressButton;
    private Search search = new Search();

    public Browser() throws IOException {

        addressLabel = new JLabel(" address: ", SwingConstants.CENTER);
        textField = new JTextField("Enter a web address..");
        textField.addActionListener(search);

        addressButton = new JButton("Go");
        addressButton.addActionListener(search);

        windowPane = new JEditorPane("");
        windowPane.setContentType("text/html");
        windowPane.setEditable(false);

        addressPanel = new JPanel(new BorderLayout());
        windowPanel = new JPanel(new BorderLayout());

        addressPanel.add(addressLabel, BorderLayout.WEST);
        addressPanel.add(textField, BorderLayout.CENTER);
        addressPanel.add(addressButton, BorderLayout.EAST);

        windowScroll = new JScrollPane(windowPane);
        windowPanel.add(windowScroll);

        Container pane = getContentPane();
        pane.setLayout(new BorderLayout());

        pane.add(addressPanel, BorderLayout.NORTH);
        pane.add(windowPanel, BorderLayout.CENTER);

        setTitle("Web Browser");
        setSize(1000, 1000);
        setVisible(true);
        setDefaultCloseOperation(EXIT_ON_CLOSE);
    }

    public class Search implements ActionListener {

        public void actionPerformed(ActionEvent ea) {

            String line;
            try {

                Socket socket = new Socket(textField.getText(), 80);
                PrintWriter out = new PrintWriter(socket.getOutputStream());
                BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
                out.print("GET / HTTP/1.1\r\n");
                out.print(textField.getText() + "\r\n\r\n");
                out.flush();
                while ((line = in.readLine()) != null) {

                    System.out.println(line);
                }
            } catch (Exception e) {

                e.printStackTrace();
            }
        }
    }

    public static void main(String[] args) throws IOException {

        Browser browser = new Browser();
    }
}

You need to have a protocol in that url.

Andrew Li
– Andrew Li

2016-10-23 23:23:31 +00:00
Commented Oct 23, 2016 at 23:23 — Andrew Li
– Andrew Li, Commented Oct 23, 2016 at 23:23
Show us the input you type in the text field.

Young Emil
– Young Emil

2016-10-23 23:47:03 +00:00
Commented Oct 23, 2016 at 23:47 — Young Emil
– Young Emil, Commented Oct 23, 2016 at 23:47

Henrique Smoco · Accepted Answer · 2016-10-24 01:13:33Z

1

The problem was because the line bellow:

windowPane = new JEditorPane("");

Just change to

windowPane = new JEditorPane();

According to JEditorPane constructor javadoc:

Creates a JEditorPane based on a string containing a URL specification.
@param url the URL
@exception IOException if the URL is null or cannot be accessed

answered Oct 24, 2016 at 1:13

Henrique Smoco

712 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Java - Creating a web browser

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related