Initializing array inside struct - C?

Question

Seem to have a memory allocation problem and think it's because in my struct, there is a pointer to an array of another struct. However, I'm not initializing this array and not sure how:

typedef struct listitem {
    struct listitem *next;
    Entry *entry;
} ListItem;

typedef struct list {
    ListItem *table[100];
} List;

List *initialize(void)
{
    List *tmp;

    if ((tmp = (List *)malloc(sizeof(List))) == NULL)
        return NULL;
    return tmp;
}

Hope that makes sense and you could help!

Puppy · Accepted Answer · 2010-10-25 23:01:50Z

3

You will need to call malloc again.

typedef struct listitem {
    struct listitem *next;
    Entry *entry;
} ListItem;

typedef struct list {
    ListItem *table[100];
} List;

List *initialize(void)
{
    List *tmp;

    if (!(tmp = (List *)malloc(sizeof(List))))
        return NULL;
    for(int i = 0; i < 100; i++) {
        tmp->table[i] = (ListItem*)malloc(sizeof(ListItem));
    }
    return tmp;
}

edited Oct 25, 2010 at 23:01

answered Oct 25, 2010 at 22:52

Puppy

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3 Comments

Igor K Over a year ago

How can you just access table though, you're not setting the pointer in the struct to it?

Puppy Over a year ago

@Igor K: Whoops, my mistake. Used to proper member functions.

Igor K Over a year ago

Thanks @DeadMG, tried this however I still get the same error with my program, although thats another question!

spacedentist · Accepted Answer · 2010-10-25 22:53:18Z

0

bzero(tmp, sizeof(*tmp));

just zeroes the contents of your struct list. If that is what you want.

answered Oct 25, 2010 at 22:53

spacedentist

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