This works
$feed = $xml->xpath('//room[@id="103"]');
I am trying to replace 103 by a variable namely $id.
I tried
$feed = $xml->xpath('//room[@id=$id]');
and
$feed = $xml->xpath('//room[@id=".$id."]');
None work.
What is the appropriate syntax for putting a variable in xpath?
When you writed $id in string, php use it like string. You should close quote like
$feed = $xml->xpath('//room[@id="'.$id.'"]');
Or write variable in {}
$feed = $xml->xpath('//room[@id="{$id}"]');
your question already answer from Mohammad but i give a more fully example with [0] at the end of the line to avoid more rows for some usages
$feed = $xml->xpath('//room[@id="'.$id.'"])[0];
also if you want result from xml with some others values inside to the root where use @attribute
$day= $_GET['Day'];
$feed = $xml->xpath('//room[@id="'.$id.'"]/Day'.$day.'')[0];
this mean if you have a xml file like harder code you can cal a day dynamic
