Can anyone explain me how to get the final value assigned to variable after completing executing while loop?
In my below code I wanted to echo the response out of while loop after fetching all the values from the rows.
Because if I put echo out of while loop it only shows 1st record.
while ($row = oci_fetch_array($array)) {
$response = $row['0']->load();
echo $response;
}
You will get the last rows value into the $response.
Cause: Every time the loop executes will assign value into the variable. But as you echo it you can see all the values as output.
So what you really need to do is storing the values in an array...
$response = array();
while ($row = oci_fetch_array($array)) {
$response[] = $row['0']->load();
}
print_r($response);
If you need further information about this , just let me know.
Since you are doing variable assignment and echo inside while loop, it will not serve your purpose.
You have to do it like below:-
$response = array(); // create an array
while ($row = oci_fetch_array($array)) {
$response[] = $row['0']->load(); // assign each value to array
}
echo "<pre/>";print_r($response);// print the array
Note:- this array will have all the values now. You can manipulate it in your desired way.Thanks
while ($row = oci_fetch_array($array)) {
$response = $row['0']->load();
}
echo $response;
Try this:
$response = [];
while ($row = oci_fetch_array($array)) {
$response[] = $row['0']->load();
}
var_dump($response);
$row['0']. It will loop till the end and then will return the row's first value cause key is 0
$response, Cause: Every time the loop executes will assign value into the variable. But as you echo it you can see all the values as output.