Lets say I have a variable which has values :
#!/bin/sh
MYVARIABLE="first,second,third"
for vars in MYVARIABLE
do
echo $vars
done
this above doesn't work what I want but it looks fine, this should print first second third without , I wan't it to be printed without , any sugestions?
Use IFS (the input field separator), eg.
#!/bin/sh
MYVARIABLE="first,second,third"
IFS=","
for vars in $MYVARIABLE
do
echo $vars
done
try
MYVARIABLE="first,second,third"
for vars in $(echo $MYVARIABLE | tr "," "\n")
do
echo $vars
done
Or if you use IFS, don't forget to set IFS back to the original one when done
MYVARIABLE="first,second,third"
OIFS=$IFS
IFS=","
for vars in $MYVARIABLE
do
echo $vars
done
IFS=$OIFS
MYVARIABLE="first,second,third"
IFS=","
set -- $MYVARIABLE
for i in ${@}; do echo $i; done
# you can also use an array in cases where you want to use the values later on
array=($@)
for i in ${!array[@]}; do echo ${array[i]}; done
set over just looping, like ar suggests?
echoes are there just to show how you can accessed the parameters after setting the variable using set.set, each field will be assigned a positional parameter, like $1, $2,$3 etc. Its useful if you want to get an exact field.Not sure what you want to do with the content of MYVARIABLE, or how do you fill it, but a very good option to deal with CSV data is to use awk.
If you have just this variable to be printed:
echo $MYVARIABLE | awk 'BEGIN { RS="," }{ print $0 }'
If you have a CSV file and need to perform calculation/transformation on the data then you should let the awk to fetch the file, using someting like:
awk 'BEGIN { FS="," ; OFS="\n" } { print $1,$2,$3 }' filename.csv
(this is just an ideia, not really related to your question)
