How can I test the values of a 2D array ?
I have a 2D array that looks like this :
array: [
["A", 24, 5],
["B", 135, 5],
["C", 2124, 5]
]
What I need is to execute a function if all the values in position 2 : array[i][2] are equal to 5.
for (i = 0; i < array.length; i++){
if (that.ptLiaison[i][2]=="5"){ //need to check all the instances of i at once
*execute function*
}
}
You can use every() method and return true/false
var array = [
["A", 24, 5],
["B", 135, 5],
["C", 2124, 5]
];
var result = array.every(function(arr) {
return arr[2] == 5;
});
if(result) console.log('Run function');You could use a a .every()
if(that.ptLiaison.every(function(row){
return row[2] == "5";
})){
}
This loops through and check that each iteration is true, and if they all are the entire operation returns true.
You could also use a more robust function:
var checkAllRows = function(array,index,value){
return array.every(function(row){
return row[index] == value;
});
}
if(checkAllRows(that.ptLiaison,2,"5")){
*do something*
}
There are several ways to do this. One of the ways is the following logic: if we want execute function when all elements equal 5, then it means if at least one element is not 5 we should not execute function. Code below:
var needExecuteFunction = true;
for (i = 0; i < array.length; i++){
if (that.ptLiaison[i][2] != "5"){
needExecuteFunction = false;
break;
}
}
if(needExecuteFunction){
// execute it.
}
