Convert numpy array of integers to 12 bit binary

Question

I neeed to convert a np array of integers to 12 bit binary numbers, in an array format. What would be the best way to go about doing so?

I've been a bit stuck so any help would be appreciated. Thanks!

Here is what I have to convert an integer to binary:

def dec_to_binary(my_int):
"""

Format a number as binary with leading zeros"""
if my_int < 4096:
    x= "{0:12b}".format(my_int)
    return int(x)
else:
    return 111111111111

I am able to turn a single integer to binary, but can't figure out how to iterate through the np array and change values without errors: see below - — Funsaized
– Funsaized, Commented Sep 17, 2016 at 13:37
Just what do you mean by "binary number"? There is no such python object. — Rory Daulton
– Rory Daulton, Commented Sep 17, 2016 at 13:42
Why would you want to create an array of 12 bit binary? If this is an attempt to save memory, be aware that solutions involving strings of '1' and '0' actually use much more memory (12 bytes) than 16 bit ints (2 bytes). — farenorth
– farenorth, Commented Sep 17, 2016 at 14:29

Nehal J Wani · Accepted Answer · 2016-09-17 13:47:55Z

1

Slight correction (replace 12b with 012b):

def dec_to_binary(my_int):
    """   
    Format a number as binary with leading zeros
    """
    if my_int < 4096:
        return "{0:012b}".format(my_int)
    else:
        return "111111111111"

Example:

In [10]: n_array = np.array([123,234,234,345, 4097])

In [11]: map(dec_to_binary, n_array)
Out[11]: 
['000001111011',
 '000011101010',
 '000011101010',
 '000101011001',
 '111111111111']

edited Sep 17, 2016 at 13:47

answered Sep 17, 2016 at 13:42

Nehal J Wani

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