I am not clear on best practice to execute unix commands from my scala based script.
A typical scala script is here
#!/bin/sh
exec scala "$0" "$0" "$@"
!#
println("args length is ", args.length)
### want to list all files in the underlying folder
val resultSet = "ls -la"????
I checked a number of posts but nothing clearly outlines a working script which can execute a unix command from scala script and perform some transformations.
import scala.sys.process._ and use the ! and !! to execute the linux commands
scala> import scala.sys.process._
scala> "ls -la" !
scala> "ls -la" !!
You can do this in the scala script as well
! returns exit code of the command after executing
!! returns the output of the command after executing
Parse the output of the
"ls -la" !!and get the files in the current dir.
Here's a simple script to get you started.
#!/usr/bin/env scala
import scala.sys.process._
// args is auto-populated
println("arg len = " + args.length)
// get listing of current files
val files: Array[String] = "ls -a".!!.split("\n")
println("5th fiile is " + files(4))
System.exit(0)
Study the process package of the Standard Library for more on capturing process output, process exit status, pipelining, etc.
