I have an array looking like this:
data =[[01, 777], [02, 888]]
Now I want to create a hash from it like below:
n_clip = [{"name"=>"01", "rep"=>"777"},{"name"=>"02", rep=>"888"}]
I tried to do this in that way:
n_clip = []
data.each do |a|
n_clip << Array[Hash[a.map {|| ["name", a.first]}], Hash[a.map {|| ["rep", a.last]}]]
end
but it doesn't work because I get:
n_clip = [[{"name"=>"01"},{"rep"="777"}], [{"name"=>"01"},{"rep"="777"}]]
and definitively it isn't what I expected.
data.map { |arr| { 'name' => arr[0], 'rep' => arr[1] } }
i would rather use symbols as hash keys
data.map { |arr| { name: arr[0], rep: arr[1] } }
If you wish to create an array of two hashes, each having the same two keys, the other answers are fine. The following handles the case where there are an arbitrary number of keys and data may contain an arbitrary number of elements.
def hashify(keys, arr_of_vals)
[keys].product(arr_of_vals).map { |ak,av| Hash[ak.zip(av)] }
end
keys = %w| name rep |
#=> ["name", "rep"]
arr_of_vals = [["01", "777"], ["02", "888"]]
hashify(keys, arr_of_vals)
#=> [{"name"=>"01", "rep"=>"777"}, {"name"=>"02", "rep"=>"888"}]
In your problem arr_of_vals must first be derived from [[1, 777], [02, 888]], but that is a secondary (rather mundane) problem that I will not address.
Another example:
keys = %w| name rep group |
#=> ["name", "rep", "group"]
arr_of_vals = [[1, 777, 51], [2, 888, 52], [1, 2, 53], [3, 4, 54]]
hashify(keys, arr_of_vals)
#=> [{"name"=>1, "rep"=>777, "group"=>51}, {"name"=>2, "rep"=>888, "group"=>52},
# {"name"=>1, "rep"=>2, "group"=>53}, {"name"=>3, "rep"=>4, "group"=>54}]
data.map { |name, rep| { 'name' => name.to_s, 'rep' => rep.to_s } }
