Run PHP file from Bash

Question

I need to run a script that will execute a php file but I can't run the PHP file from Bash Script

Test.sh:

#!/bin/sh
php /home/username/public_html/Test3/Test.php

Where is the error?

/var/log/cron :

Sep  7 22:56:01 srv CROND[4344]: (root) CMD (sh /home/Username/public_html/Test3/test.sh)

Test.php

<?php
$servername = "localhost";
$username = "";
$password = "";
$dbname = "";

try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $date = date('h:i:s');
    $sql = "UPDATE deneme SET CRONTEST='".$date."' WHERE id=1";

    $stmt = $conn->prepare($sql);

    $stmt->execute();

    echo $stmt->rowCount() . " records UPDATED successfully";
    }
catch(PDOException $e)
    {
    echo $sql . "<br>" . $e->getMessage();
    }

$conn = null;
?>

What is the output if you simply type php -v in bash?

Blake
– Blake

2016-09-07 19:39:31 +00:00
Commented Sep 7, 2016 at 19:39 — Blake
– Blake, Commented Sep 7, 2016 at 19:39
Can you print the error you have in console?

Marco Santarossa
– Marco Santarossa

2016-09-07 19:39:33 +00:00
Commented Sep 7, 2016 at 19:39 — Marco Santarossa
– Marco Santarossa, Commented Sep 7, 2016 at 19:39
Have you added x to file?

u_mulder
– u_mulder

2016-09-07 19:40:21 +00:00
Commented Sep 7, 2016 at 19:40 — u_mulder
– u_mulder, Commented Sep 7, 2016 at 19:40
@MarcoSantarossa There are no errors

Editor
– Editor

2016-09-07 19:50:17 +00:00
Commented Sep 7, 2016 at 19:50 — Editor
– Editor, Commented Sep 7, 2016 at 19:50
@DuaneLortie pastebin.com/sFzSbF8T (?)

Editor
– Editor

2016-09-07 20:04:12 +00:00
Commented Sep 7, 2016 at 20:04 — Editor
– Editor, Commented Sep 7, 2016 at 20:04

Duane Lortie · Accepted Answer · 2016-09-07 20:10:42Z

4

Multiple ways to get this working. My first choice, call the PHP script directly from cron. To do that, make sure your php script is executable (chmod 755) Make sure the CLI php script starts with..

#!/usr/bin/php
<?php

From a shell, type 'which php' and change the '/usr/bin...' line accordingly. Once those steps are done, your cron entry might look like . . .

*/5 * * * * /usr/bin/php -f /var/www/script.php

and again, make sure you point to php's actual location.
Tried explaining in comments, ran out of room :/

answered Sep 7, 2016 at 20:10

Duane Lortie

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Comments

hamshotFIRST · Accepted Answer · 2019-03-14 14:25:42Z

1

I know it's old, but I just ran into this today. Whenever a Bash script does not execute a PHP script (despite having correct permissions and the "php" command working on its own), I found using the full path to PHP resolves it. i.e.

#!/bin/bash

other code
...
/usr/bin/php /home/username/public_html/Test3/Test.php

You can use which php and whereis php to determine the correct path.

answered Mar 14, 2019 at 14:25

hamshotFIRST

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Comments

Editor · Accepted Answer · 2016-09-07 20:50:04Z

0

I solved my question this method:

#!/bin/bash

data=$(/usr/bin/php -q /home/username/public_html/Test3/Test.php);

But I can't variables, for example:

#!/bin/bash

data=$(/usr/bin/php -q /home/username/public_html/Test3/Test.php name=Saracoglu);

Its not working. I'm searching..

answered Sep 7, 2016 at 20:50

Editor

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2 Comments

heemayl Over a year ago

Isn't this the same thing i have written in my answer?

Editor Over a year ago

@heemayl You don't have in answer data=$( binPath -q path );

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