Can I build array what includes different types? For example:
[1, 2, "apple", true]
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2While there are ways to do this in Go, and perhaps there are valid use cases, I would recommend not doing this. It looks like you're trying to translate your Ruby knowledge and experience to Go, and this probably isn't a good idea. Go's typing is different from Ruby's, and requires a different way of thinking and programming.Martin Tournoij– Martin Tournoij2016-09-07 18:22:57 +00:00Commented Sep 7, 2016 at 18:22
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@Carpetsmoker thanks, I see what you mean, but I just wanna to know Go abilityOleh Sobchuk– Oleh Sobchuk2016-09-07 18:24:20 +00:00Commented Sep 7, 2016 at 18:24
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If you are new to Go: Maybe it would be helpful to stick to "proper", safe and idiomatic Go and leave the borders of the Go universe unexplored for a few months?Volker– Volker2016-09-08 07:14:14 +00:00Commented Sep 8, 2016 at 7:14
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2 Answers
You can do this by making a slice of interface{} type. For example:
func main() {
arr := []interface{}{1, 2, "apple", true}
fmt.Println(arr)
// however, now you need to use type assertion access elements
i := arr[0].(int)
fmt.Printf("i: %d, i type: %T\n", i, i)
s := arr[2].(string)
fmt.Printf("b: %s, i type: %T\n", s, s)
}
Read more about this here.
3 Comments
abhink
@Tim: fixed. Thanks
Uvelichitel
To be precise it's a slice of same type - interface{}, not an array with different types elements.
Depending on the situation, you might be able to use a struct instead:
package main
import "fmt"
type array struct {
one, two int
fruit string
truth bool
}
func main() {
arr := array{1, 2, "apple", true}
fmt.Println(arr)
}
1 Comment
Joshua Oluikpe
The question clearly stated array, why use a struct?