PHP Remove Quotes from JSON String of CURL Response

Question

 //...snip..
    $result = curl_exec($ch);
    curl_close($ch);
    return $result;

The response of a php curl request is showing as

"{\"result\":\"success\",\"entry\":\"22\",\"confirm\":\"yes\"}"

However, the output should not have \ in front of the quotes. How do I remove those quotes and return as proper JSON

{
"result":"success",
"entry":"22",
"confirm":"yes"
}

Few options I tried are return print_r($result). This is returning as expected, but I think this is not proper way.

PHP version - 5.6.16

jeroen · Accepted Answer · 2016-08-10 10:19:46Z

2

Your output is correct and you have valid json; which is a string.

All you have to do, is decode it:

$s = "{\"result\":\"success\",\"entry\":\"22\",\"confirm\":\"yes\"}";

var_dump(json_decode($s));

An example.

answered Aug 10, 2016 at 10:19

jeroen

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5 Comments

blakcaps Over a year ago

But json_decode removes keys like result, entry, confirm.

jeroen Over a year ago

@blakcaps What do you mean, have you checked the example? It returns an object with the keys result, entry, etc.

Mittul Chauhan Over a year ago

@blakcaps yes jeroen is right .. it returns an object with keys only .. please check.

blakcaps Over a year ago

I am trying to return the $result from a method. How can I use var_dump for method return

jeroen Over a year ago

@blakcaps The var_dump() was just to show the results, if you need an object (or array...), just return the result of json_decode().

Alok Patel · Accepted Answer · 2016-08-10 10:28:20Z

1

You can use stripslashes() to remove slashes from the JSON String then decode the JSON String using json_decode().

Like this,

$json_string="{\"result\":\"success\",\"entry\":\"22\",\"confirm\":\"yes\"}";
$json_string=stripslashes($json_string);
$json_array=json_decode($json_string,true);
print_r($json_array);

Above method just remove the slashes from the string and uses json_decode() to decode the JSON String.

But you can also decode the string directly with the slashes. (Thanks to @jeroen) Like this,

$json_string="{\"result\":\"success\",\"entry\":\"22\",\"confirm\":\"yes\"}";
$json_array=json_decode($json_string,true);
print_r($json_array);

Second parameter in json_decode() denotes you want to parse the JSON String in array instead of object which is default behavior.

edited Aug 10, 2016 at 10:28

answered Aug 10, 2016 at 10:19

Alok Patel

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2 Comments

jeroen Over a year ago

There is no need to use stripslashes(), you can decode this directly.

mukund Over a year ago

Its true, stripslashes not required. If you add stripslashes json string will break

mukund · Accepted Answer · 2016-08-10 10:29:49Z

0

Simply use following header option in your curl, will return json object:

curl_setopt($ch, CURLOPT_HTTPHEADER, array('Accept: application/json'));
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));

Because default accept type is Text/Plain so it will return you parsed sting. By setting above header you will receive json object.

edited Aug 10, 2016 at 10:29

answered Aug 10, 2016 at 10:22

mukund

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