New to this whole concept of prototypes in Javascript and might be confused.
Let's say I have a class called Widget, defined as:
var Widget = function (options) {
// constructor code here
}
Widget.prototype.constructor = Widget;
Widget.prototype.myGreatFunction = function(){}
Should I be able to call Widget.myGreatFunction(); or do I need to call Widget.prototype.myGreatFunction()? to run the great function?
If you use your constructor function to make an instance, you can use the function from there:
var w = new Widget();
w.myGreatFunction();
You can also use the function by referring to it via the prototype:
Widget.prototype.myGreatFunction();
Ideal way of doing so is creating an instance and using the prototypal functions.
Nevertheless as the function is stored in Widget.prototype.myGreatFunction you can definitely access it.
The functions defined in the prototype are shared resources and thats the prime advantage of using it in this manner.
var Widget = function (options) {
// constructor code here
}
Widget.prototype.constructor = Widget;
Widget.prototype.myGreatFunction = function(i){console.log('myGreatFunction', i);};
var a = new Widget();
a.myGreatFunction(1);
var b = new Widget();
b.myGreatFunction(2);
Widget.prototype'sconstructorproperty already refers toWidget. You don't needWidget.prototype.constructor = Widget;unless you replace the object thatWidget.prototyperefers to.