split string list into sublist in python

Question

Looking for a way to split the following string list into sublist and print using a for loop.

[[[u'Book1', None, u'Thriller', u'John C', u'07/12/2012'],
[u'Book2', u'1', u'Action', u'Tom B', u'07/12/2012'],
[u'Book3', None, u'Romance', u'Angie P', u'07/12/2012'],
[u'Book4', None, u'Comedy', u'Tracy N', u'07/12/2012'],
[u'Book5', None, u'Drama', u'Kumar P', u'07/12/2012'],
[u'Book6', None, u'Action&Drama', u'Ben J', u'07/12/2012']]]

Any suggestion please.

based on [u'Book1', None, u'Thriller', u'John C', u'07/12/2012'] — kumar
– kumar, Commented Jul 29, 2016 at 17:06

Sandeep Singh Rawat · Accepted Answer · 2016-07-29 17:10:47Z

2

Are you looking for this?

def testString():
    input = [[
    [u'Book1', None, u'Thriller', u'John C', u'07/12/2012'],
    [u'Book2', u'1', u'Action', u'Tom B', u'07/12/2012'],
    [u'Book3', None, u'Romance', u'Angie P', u'07/12/2012'],
    [u'Book4', None, u'Comedy', u'Tracy N', u'07/12/2012'],
    [u'Book5', None, u'Drama', u'Kumar P', u'07/12/2012'],
    [u'Book6', None, u'Action&Drama', u'Ben J', u'07/12/2012']
    ]]
    for subarray in input[0]:
        print (subarray)

This is the output

['Book1', None, 'Thriller', 'John C', '07/12/2012']
['Book2', '1', 'Action', 'Tom B', '07/12/2012']
['Book3', None, 'Romance', 'Angie P', '07/12/2012']
['Book4', None, 'Comedy', 'Tracy N', '07/12/2012']
['Book5', None, 'Drama', 'Kumar P', '07/12/2012']
['Book6', None, 'Action&Drama', 'Ben J', '07/12/2012']

answered Jul 29, 2016 at 17:10

Sandeep Singh Rawat

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Comments

Dataman · Accepted Answer · 2016-07-29 17:10:28Z

1

Your question is a bit vague! If I understood your question correctly, you can do it like this:

a = [[[u'Book1', None, u'Thriller', u'John C', u'07/12/2012'], [u'Book2', u'1', u'Action', u'Tom B', u'07/12/2012'], [u'Book3', None, u'Romance', u'Angie P', u'07/12/2012'], [u'Book4', None, u'Comedy', u'Tracy N', u'07/12/2012'], [u'Book5', None, u'Drama', u'Kumar P', u'07/12/2012'], [u'Book6', None, u'Action&Drama', u'Ben J', u'07/12/2012']]]
for v in a[0]:
    print(v)

answered Jul 29, 2016 at 17:10

Dataman

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