Split string into array regex php

Question

I need to split the string bellow into array keys like in this format:

string = "(731) some text here with number 2 (220) some 54 number other text here" convert into:

array( 
  '731' => 'some text here with number 2', 
  '220' => 'some 54 number other text here' 
);

I have tried:

preg_split( '/\([0-9]{3}\)/', $string );

and got:

array ( 
  0 => 'some text here', 
  1 => 'some other text here' 
);

I think, you should represent the data in question in little better format. It will be easier for community to read it and reply. — Bhavik Shah
– Bhavik Shah, Commented Jul 29, 2016 at 9:15
The requirements are too vague. Could you at least provide the expected output for the provided input string? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 29, 2016 at 9:15
I'm guessing you want the numbers in the string to be the keys in your array, correct? — Henders
– Henders, Commented Jul 29, 2016 at 9:29

Mariano · Accepted Answer · 2016-07-29 12:11:12Z

8

Code

$string = "(731) some text here with number 2 (220) some 54 number other text here";

preg_match_all("/\((\d{3})\) *([^( ]*(?> +[^( ]+)*)/", $string, $matches);
$result = array_combine($matches[1], $matches[2]);

var_dump($result);

Output

array(2) {
  [731]=>
  string(28) "some text here with number 2"
  [220]=>
  string(30) "some 54 number other text here"
}

ideone demo

Description

The regex uses

$(\d{3})$ to match 3 digits in parentheses and captures it (group 1)
\ * to match the spaces in between keys and values
([^( ]*(?> +[^( ]+)*) to match everything except a ( and captures it (group 2)
This subpattern matches exactly the same as [^(]*(?<! ) but more efficiently, based on the unrolling-the-loop technique.

*Notice though that I am interpreting a value field cannot have a ( within. If that is not the case, do tell and I will modify it accordingly.

After that, we have $matches[1] with keys and $matches[2] with values. Using array_combine() we generate the desired array.

edited Jul 29, 2016 at 12:11

answered Jul 29, 2016 at 10:38

Mariano

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3 Comments

revo Over a year ago

Up-voted only for the use of array_combine(). Two issues with your RegEx: 1- Unnecessary possessive quantifiers. 2- Ignoring parenthesis from being within strings (which may be there).

revo Over a year ago

Why should you think there could be a failure case for \s*+ and [^( ]*+?

Mariano Over a year ago

Hah! Right! No idea what I was thinking. Thanks for the heads-up

n-dru · Accepted Answer · 2016-07-29 09:43:02Z

1

Try this:

$string = "(731) some text here with number 2 (220) some 54 number other text here";
$a = preg_split('/\s(?=\()/', $string);//split by spaces preceding the left bracket
$res = array();
foreach($a as $v){
    $r = preg_split('/(?<=\))\s/', $v);//split by spaces following the right bracket
    if(isset($r[0]) && isset($r[1])){
        $res[trim($r[0],'() ')] = trim($r[1]);//trim brackets and spaces
    }
}
print_r($res);

Output:

Array
(
    [731] => some text here with number 2
    [220] => some 54 number other text here
)

DEMO

If you want to limit it only to those numbers in brackets that have 3 digits, just modify the lookarounds:

$a = preg_split('/\s(?=\([0-9]{3}\))/', $string);

edited Jul 29, 2016 at 9:43

answered Jul 29, 2016 at 9:37

n-dru

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Comments

Avishake · Accepted Answer · 2016-07-29 09:47:39Z

1

you can try this one,

<?php
$str="(731) some text here (220) some other text here";
echo $str .'<br>';
$arr1=explode('(', $str);
$size_arr=count($arr1);
$final_arr=array();
for($i=1;$i<$size_arr; $i++){
    $arr2=explode(')', $arr1[$i]);
    $final_arr[$arr2[0]]=trim($arr2[1]);
}
echo '<pre>';
print_r($final_arr);
?>

Use this link to test the code, Click Here.

I try to use the simple syntax. Hope everybody can understand.

edited Jul 29, 2016 at 9:47

answered Jul 29, 2016 at 9:39

Avishake

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Comments

Wolfgang · Accepted Answer · 2016-07-29 10:12:49Z

1

I'm pretty sure that defining the keys is not possible, as the regex will add matches coninuously. I would define 2 regex, one for the keys:

preg_match_all("/(\()([0-9]*)(\))\s/", $input_lines, $output_array);

you will find your keys in $output_array[2]. And one for the texts (that looks quite the same):

preg_split("/(\()([0-9]*)(\))\s/", $input_line);

After that, you can build your custom array iterating over both. Make sure to trim the strings in the second array when inserting.

answered Jul 29, 2016 at 10:12

Wolfgang

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Comments

revo · Accepted Answer · 2016-07-29 10:25:34Z

1

Using preg_replace_callback() you can quickly achieve what you desire (when only parentheses contain 3 digits):

$string = "(731) some text here with number 2 (220) some 54 number other text here";
$array = array();
preg_replace_callback('~(\((\d{3})\))(.*?)(?=(?1)|\Z)~s', function($match) use (&$array) {
    $array[$match[2]] = trim($match[3]);
}, $string);
var_dump($array);

Output:

array(2) {
  [731]=>
  string(28) "some text here with number 2"
  [220]=>
  string(30) "some 54 number other text here"
}

edited Jul 29, 2016 at 10:25

answered Jul 29, 2016 at 10:20

revo

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Comments

r3npi2 · Accepted Answer · 2016-07-29 10:29:33Z

Maybe you can add PREG_SPLIT_DELIM_CAPTURE flag to preg_split. From preg_split man page (http://php.net/manual/en/function.preg-split.php)

PREG_SPLIT_DELIM_CAPTURE

If this flag is set, parenthesized expression in the delimiter pattern will be captured and returned as well.

So if you change your code to:

$results = preg_split('/\(([0-9]+)\)/s', $data,null,PREG_SPLIT_DELIM_CAPTURE);

You will obtain an array similar to:

Array
(
    [0] => KS/M/ 2013/1238 
    [1] => 220
    [2] =>  23/12/2013 
    [3] => 300
    [4] => 

    [5] => 731
    [6] =>  VALDETE BUZA ADEM JASHARI- PRIZREN, KS 
    [7] => 526
    [8] => 

    [9] => 591
    [10] => 

    [11] => 740
    [12] => 


    [13] => 540
    [14] =>  DEINA 
    [15] => 546
    [16] => 


    [17] => 511
    [18] =>  3 Preparatet për zbardhim dhe substancat tjera për larje rrobash; preparatet për pastrim, shkëlqim, fërkim dhe gërryerje; sapunët; parfumet, vajrat esencialë, preparatet kozmetike, losionet për flokë, pasta për dhembe
14 Metalet e cmueshme dhe aliazhet e tyre; mallrat në metale të cmueshme ose të veshura me to, që nuk janë përfshire në klasat tjera; xhevahirët, gurët e cmueshëm; instrumentet horologjike dhe kronometrike (për matjen dhe regjistrimin e kohës)
25 Rrobat, këpucët, kapelat
35 Reklamim, menaxhim biznesi; administrim biznesi; funksione zyre
)

What you should do is to loop over the array ignoring first element in that case:

$myArray = array();
$myKey = '';
foreach ($results as $k => $v) {
  if ( ($k > 0) && ($myKey == '')) {
    $myKey = $v;
  } else if ($k > 0) {
    $myArray[$myKey] = $v; 
    $myKey = '';
  }
}

EDIT: This answer is for:

$data ='KS/M/ 2013/1238 (220) 23/12/2013 (300)
(731) VALDETE BUZA ADEM JASHARI- PRIZREN, KS (526)
(591)
(740)

(540) DEINA (546)

(511) 3 Preparatet për zbardhim dhe substancat tjera për larje rrobash; preparatet për pastrim, shkëlqim, fërkim dhe gërryerje; sapunët; parfumet, vajrat esencialë, preparatet kozmetike, losionet për flokë, pasta për dhembe
14 Metalet e cmueshme dhe aliazhet e tyre; mallrat në metale të cmueshme ose të veshura me to, që nuk janë përfshire në klasat tjera; xhevahirët, gurët e cmueshëm; instrumentet horologjike dhe kronometrike (për matjen dhe regjistrimin e kohës)
25 Rrobat, këpucët, kapelat
35 Reklamim, menaxhim biznesi; administrim biznesi; funksione zyre';

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