%matplotlib inline ValueError

Question

When I use %matplotlib inline in my program, I get a ValueError. What does this error mean, and how can I resolve it?

Here is the error:

Traceback (most recent call last):
File "main.py", line 40, in <module>
ct.iloc[:-1,:-1].plot(kind='bar',stacked=True,color=['red','blue'],grid='false')
File "/usr/lib/python2.7/dist-packages/pandas/tools/plotting.py", line  1735, in plot_frame
plot_obj.generate()
File "/usr/lib/python2.7/dist-packages/pandas/tools/plotting.py", line 907, in generate
self._adorn_subplots()
File "/usr/lib/python2.7/dist-packages/pandas/tools/plotting.py", line  1012, in _adorn_subplots
ax.grid(self.grid)
File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 2176, in grid
b = _string_to_bool(b)
File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 54, in _string_to_bool
raise ValueError("string argument must be either 'on' or 'off'")
ValueError: string argument must be either 'on' or 'off'

Nimantha · Accepted Answer · 2023-11-10 06:31:59Z

3

Using the final line of your traceback can be very useful. One of the string arguments you are passing should only be 'on' or 'off'. Based on this we can then look at the grid option as this is a boolean option.

I tested this like so:

%matplotlib inline
import matplotlib.pyplot as plt
plt.plot([23,4],[4,6])
plt.grid('false')

giving the same error you got. To fix this you should use either grid = 'off' or grid = False as options. In my example above I would change that to plt.grid('off')

edited Nov 10, 2023 at 6:31

Nimantha

6,5276 gold badges32 silver badges78 bronze badges

answered Jul 25, 2016 at 18:23

Ianhi

3,2101 gold badge27 silver badges27 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

%matplotlib inline ValueError

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related