Format git log output in PowerShell

Question

I fetch my latest git log message via $commitMessage = git log -1 --pretty=full 2>&1. What confuses me is that $commitMessage.contains("`n") returns False, but there are clearly line breaks in $commitMessage.

How can I replace all linebreaks in $commitMessage?

Example content of $commitMessage:

commit ca82a6dff817ec66f44342007202690a93763949
Author: Scott Chacon <[email protected]>
Date:   Mon Mar 17 21:52:11 2008 -0700

    changed the version number

Thanks

$commitMessage is an array of strings, not a single multi-line string. You can concatenate them with the -join operator — Mathias R. Jessen
– Mathias R. Jessen, Commented Jul 19, 2016 at 9:55

vonPryz · Accepted Answer · 2016-07-19 09:56:01Z

5

It's likely that $commitMessage is actually an array of strings. To find out, use the .GetType() method like so,

$commitMessage.GetType()

This will tell what kind of object you are working with. To join an array of strings, use the -join operator like so,

# A demo array of strings
$commitMessage = @()
$commitMessage += "commit ca82a6dff817ec66f44342007202690a93763949"
$commitMessage += "Author: Scott Chacon <[email protected]>"
$commitMessage += "Date:   Mon Mar 17 21:52:11 2008 -0700"
$commitMessage
commit ca82a6dff817ec66f44342007202690a93763949
Author: Scott Chacon <[email protected]>
Date:   Mon Mar 17 21:52:11 2008 -0700

# Join the cells with using arbitary separator
$commitMessage -join '|'
commit ca82a6dff817ec66f44342007202690a93763949|Author: Scott Chacon <[email protected]>|Date:   Mon Mar 17 21:52:11 2008 -0700

answered Jul 19, 2016 at 9:56

vonPryz

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