How to find item in array using jQuery?

Question

So I have this array:

var statuses = { New:1, Addressed:2, Rejected:3, Recovered:4, Billed:5, Completed:6 };

And I'd like to basically search the array for the "Rejected" key and have it return the value, so I can then go back/forth in the array as needed.

I've tried this, but it always fails with a "-1" saying it can't find it.

jQuery.inArray("Rejected", statuses)

What you have is not an array. It's a javascript object with many properties. Arrays are denoted with square brackets. Don't mistake those two different notions. — Darin Dimitrov
– Darin Dimitrov, Commented Oct 1, 2010 at 19:10

Skilldrick · Accepted Answer · 2010-10-01 19:09:42Z

2

"Rejected" in statuses;

No need for jQuery.

If you want the value, do:

statuses["Rejected"];

This will return undefined if "Rejected" is not in the object.

As the others have said, literals of the form {blah: value, blah2: value} represent objects, and those like [value1, value2, value2] represent arrays.

answered Oct 1, 2010 at 19:09

Skilldrick

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Matt · Accepted Answer · 2010-10-01 19:10:35Z

2

That's not an array, that's an object.

It's a lot easier:

if (statuses.hasOwnProperty("Rejected")) {
  // It has it
  var valueOfRejected = statuses.Rejected

  // valueOfRejected now equals 3
} else {
  // It doesn't
}

You can safely retrieve the Rejected key, even if it doesn't exist in the Object without throwing an error; the retrieved value will just equal undefined.

answered Oct 1, 2010 at 19:10

Matt

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1 Comment

Christian C. Salvadó Over a year ago

If a property doesn't exist on an object, and you try to access it, there's no error thrown, it will simply produce undefined e.g. ({}).iDontExist === undefined;

andres descalzo · Accepted Answer · 2010-10-01 19:43:44Z

0

var statuses = { New:1, Addressed:2, Rejected:3, Recovered:4, Billed:5, Completed:6 };

$.inJsonObject = function(ind, obj) {

    return (typeof obj[ind] != 'undefined');

};

$.inJsonObject('Rejected', statuses); // true / false

answered Oct 1, 2010 at 19:43

andres descalzo

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