Load an array variable from a file

Question

I have the following code which uses an array to write the result to file. I want to create another array to read the celebrities array from another file.

<?php
require("class.XMLHttpRequest.php");
function hot($news){
 $url="https://localhost/search.aspx?search=".$news.""; 
 $ajax=new XMLHttpRequest();
 $ajax->setRequestHeader("Cookie","Cookie: host");
 $ajax->open("GET",$url,true);
 $ajax->send(null);
 if($ajax->status==200){
  $rHeader=$ajax->getResponseHeader("Set-Cookie");
  if(substr_count($rHeader, "Present!")>0) { return true; }
 }else{ return false; }
} 
$celebrities = array('britney','gaga','carol');
$filename = 'result.txt';
$handle = fopen($filename, 'a');
foreach($celebrities as $celebrity)
{
    if(hot($celebrity)) { fwrite($handle, "{$celebrity}\r\n"); };
}
fclose($handle);
?>

I would also like to load the $celebrities array from a file instead of

$celebrities = array('britney','gaga','carol');

I couldnt get this to work. What am I doing wrong?

<?php
$handle = @fopen('array.txt', "r"); 
if ($handle) { 
   while (!feof($handle)) { 
       $celebrities[] = fgets($handle, 4096); 
   } 
   fclose($handle); 
} 
?>

I'd love to see the hot function.

Kevin
– Kevin

2010-09-30 14:42:53 +00:00
Commented Sep 30, 2010 at 14:42 — Kevin
– Kevin, Commented Sep 30, 2010 at 14:42
Please don't yell at us.

GZipp
– GZipp

2010-09-30 14:48:12 +00:00
Commented Sep 30, 2010 at 14:48 — GZipp
– GZipp, Commented Sep 30, 2010 at 14:48

Daniel R · Accepted Answer · 2010-09-30 14:50:37Z

2

$celebrities = file('array.txt'); // possibly add an array_filter()

// OR
$celebrities = explode('\r\n', file_get_contents('array.txt'));

answered Sep 30, 2010 at 14:50

Daniel R

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3 Comments

Daniel R Over a year ago

I used the wrong file from your question, you probably want result.txt, but it was really only meant as an example. If you have one celebrity per line in a file either should work.

adam Over a year ago

yeah but i want to take an array from a file then use the function and the result goes to another file

GZipp Over a year ago

If you use file('array.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); then the newline characters and blank lines will be filtered out.

Mischa · Accepted Answer · 2010-09-30 21:50:57Z

1

I don't see any problem with your code. What exactly doesn't work? Any error messages?

Why are you reading the file into an array? My suggestion:

$read_file = fopen('array.txt', 'r');
$write_file = fopen('result.txt', 'a');

while(!feof($read_file))
{
    $celebrity = trim(fgets($read_file));
    if(hot($celebrity)) { fwrite($write_file, "{$celebrity}\r\n"); }
}

fclose($write_file);
fclose($read_file);

edited Sep 30, 2010 at 21:50

answered Sep 30, 2010 at 14:48

Mischa

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6 Comments

adam Over a year ago

your ideea is great, that's actually what i want to do , load from a a file then write to another, you example doent give any errors but my result.txt is empty

adam Over a year ago

in your example it seems like after reading the file the info doesnt go in variable celebrity so i gues that's y nothing is written

Mischa Over a year ago

Sounds like for some reason you cannot read array.txt. Maybe something about file encoding, line endings or permissions. Sorry, I don't have time anymore now. I will check this question again later.

adam Over a year ago

i think it misses the old foreach($celebrities as $celebrity) line there,

adam Over a year ago

found it ! i must use $celebrity = trim(fgets($read_file)); and also replace $handlewith $write_file

|

Kevin · Accepted Answer · 2010-09-30 14:49:01Z

0

Since you're separating each array entry by a newline/carriage return, you should read in the contents of the file line by line and assign each to your array, which it looks like you're doing. Perhaps declaring the array before you use it will help, i.e. $celebrities = array(); before your loop. Otherwise it looks like $celebrities is getting redefined every time your loop iterates.

If you provide more information on what is not working (parse error? contents of the array?) then I could provide a more detailed answer.

If the code doesn't give an error, print out the contents of the array print_r($celebrities); and show us your output.

edited Sep 30, 2010 at 14:49

answered Sep 30, 2010 at 14:43

Kevin

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1 Comment

tamasd Over a year ago

"$var" and "{$var}" is the same in PHP.

Edgard Leal · Accepted Answer · 2015-06-05 12:45:11Z

0

You can also do that for work in OSX linux and Windows:

$content = file_get_contents($file_name);
$array = explode(PHP_EOL, file_get_contents('fileName.txt'));

The PHP_EOL return the end of line for current OS.

answered Jun 5, 2015 at 12:45

Edgard Leal

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Comments

Ron Piggott · Accepted Answer · 2015-06-05 12:56:35Z

0

This is how I store variables in a file:

<?php

    return array(
        'db' => array(
            'host' => '127.0.0.1',
            'port' => '3306',
            'database' => 'someDatabase',
            'username' => 'someUsername',
            'password' => 'somePassword'
        )
    );

Then I assign the variables to $MariaDB with this command:

$MariaDB = include("read.php");

This is how an example of I access the variables:

$dsh = "mysql:host=" . $MariaDB['db']['host'] . ";dbname=" . $MariaDB['db']['database'];
$dbh = new PDO($dsh, $MariaDB['db']['username'], $MariaDB['db']['password'] );

answered Jun 5, 2015 at 12:56

Ron Piggott

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