String value = myInput.getText().toString();
I want to put string value into JSONObject.put("STRING",value) method but it's not working..
See the attached screen shot and tell how to resolve this.
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use try catch for thatAditya Vyas-Lakhan– Aditya Vyas-Lakhan2016-07-07 11:30:53 +00:00Commented Jul 7, 2016 at 11:30
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you forgot to attach screenshot.Shridutt Kothari– Shridutt Kothari2016-07-07 11:31:27 +00:00Commented Jul 7, 2016 at 11:31
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My question is not about what error is coming..Kamal Oberoi– Kamal Oberoi2016-07-07 11:31:56 +00:00Commented Jul 7, 2016 at 11:31
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why try catch is compulsory for thatKamal Oberoi– Kamal Oberoi2016-07-07 11:36:13 +00:00Commented Jul 7, 2016 at 11:36
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because may be Exception comes so catch block handleNitesh Pareek– Nitesh Pareek2016-07-07 11:36:44 +00:00Commented Jul 7, 2016 at 11:36
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3 Answers
Add try.. catch
String data = "";
String val = "hello";
try {
JSONObject j = new JSONObject(data);
j.put("VAL", val);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
1 Comment
Nitesh Pareek
because may be Exception comes so catch block handle
You should wrap the code inside try-catch
try {
JSONObject j = new JSONObject(data);
} catch (JSONException e) {
e.printStackTrace();
}
Why try-catch is compulsary??
There are 2 kinds of exceptions: Checked and Unchecked.
Checked exception can be considered one that is found by the compiler, and the compiler knows that it has a chance to occur, so you need to catch or throw it.
Unchecked exception is a Runtime Exception which means these are exceptional conditions that are internal to the application, and that the application usually cannot anticipate or recover from.
JSONException is a type of Checked exception. Checked exceptions needs to be handled at compile time itself.
new JSONObject(data) will throw JSONException if the parse fails or doesn't yield a JSONObject. So it is recommended to wrap it inside a try-catch block at compile time itself & the underlying IDE will show an error message for the same.
Comments
Put your code in try.. catch block because may be Exception occur
try{
JSONObject params = new JSONObject(data);
}
catch (JSONException e)
{
e.printStackTrace();
}