Ruby string to hash values

Question

I just started to learn Ruby!

I have the following string:

"Mark Smith, 29"

and I want to convert it to hash, so it looks like this:

{:name=>"Mark", :surname=>"Smith", :age=>29}

I've written the following code, to cut the input:

a1 = string.scan(/\w+|\d+/)

Now I have an array of strings. Is there an elegant way to convert this to hash? I know I can make three iterations like this:

pers = Hash.new
pers[:name] = a1[0]
pers[:surname] = a1[1]
pers[:age] = a1[2]

But maybe there is a way to do it using .each method or something like this? Or maybe it is possible to define a class Person, with predefined keys (:name, :surname, :age), and then just "throw" my string to an instance of this class?

Arup Rakshit · Accepted Answer · 2016-06-18 15:51:44Z

9

Yes, you can do like,

%i(name surname age)
   .zip(string.scan(/\w+|\d+/))
   .to_h
# => {:name=>"Mark", :surname=>"Smith", :age=>"29"}

Or, you can take the benefit of Struct, like:

Person = Struct.new(:name, :surname, :age )
person = Person.new( *string.scan(/\w+|\d+/) )
person.age  # => "29"
person.name # => "Mark"

edited Jun 18, 2016 at 15:51

answered Jun 18, 2016 at 15:46

Arup Rakshit

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1 Comment

Maciek Over a year ago

Thank you for help and showing me Struct and zip - I will read about these elements to fully understand them.

Cary Swoveland · Accepted Answer · 2016-06-18 19:09:58Z

2

For simplicity, precision and clarity I'd do it like so:

"Mark Smith, 29" =~ /(\w+)\s+(\w+),\s+(\d+)/
  #=> 0 
{ :name=> $1, :surname=> $2, :age=> $3.to_i }
  #=> {:name=>"Mark", :surname=>"Smith", :age=>29}

Unlike /\w+|\d+/, this regex requires "Mark" and "Smith" to be strings and "29" to be digits.

answered Jun 18, 2016 at 19:09

Cary Swoveland

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