Storing multiple function values in a string/array (Python)

Question

I am attempting to store multiple function values in an array, in order to graph a function in python.

For the example, let's define that the function is y= x^2 and the argument values wanted are 1,2 and 3. The code I attempted is the following :

def ExampleFunction (x):
        return x**2
ArgumentValues=range(3)       
FunctionValues=ExampleFunction(ArgumentValues)

Unfortunately running the code results in an error:

TypeError: unsupported operand type(s) for ** or pow(): 'range' and 'int'

How can I return many function values into a string/array in python? As a result I would want the "function values" take the following form:

1,4,9

Klaus D. · Accepted Answer · 2016-05-30 15:15:50Z

2

Use a list comprehension:

results = [ExampleFunction(x) for x in range(3)]

answered May 30, 2016 at 15:15

Klaus D.

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Comments

khelili miliana · Accepted Answer · 2016-05-30 15:25:46Z

1

This code answer :

def ExampleFunction (x):
    list_fn = []
    for item in x :
        list_fn.append(item**2)
    return list_fn 
ArgumentValues=range(3)       
FunctionValues=ExampleFunction(ArgumentValues)

Or this code :

def ExampleFunction (x):
    return x**2
ArgumentValues=range(3)   
FunctionValues= [ExampleFunction(x) for x in ArgumentValues]

edited May 30, 2016 at 15:25

answered May 30, 2016 at 15:15

khelili miliana

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1 Comment

Asish M. Over a year ago

You are still returning only 1 value with your function.

Jared Goguen · Accepted Answer · 2016-05-30 16:52:17Z

1

This is the perfect usage for map.

map(lambda x: x**2, range(3))
# [0, 1, 4]

In Python 3.X, map will return a map object instead of a list, so if you want to reuse it, you need to explicitly convert it to a list.

answered May 30, 2016 at 16:52

Jared Goguen

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