Print, loop, Indentation, Python

Question

I need a pit of help. I am currently learning python, and I have python 2.7.8 I am looking to build a simple program that will help to count the vowels in my word. Here is the code:

count = 0
total = 0
for v in "bonbon":
  count += 1
  if v == 'e' or v == 'o' or v == 'u' or v == 'a':
    print('the number of vowel in your word is ' +str(total))

Why does it print twice? 1- the number of my vowel is 0 and then the number of my is 2

Could someone help me please? Thanks guys

For future questions, inspect the toolbar above the text field when you ask/edit a question. There is a code block button marked with {}. If you select your code and click this button it is automatically correctly indented, and displayed correctly in the question. — Sumurai8
– Sumurai8, Commented May 28, 2016 at 15:50

Ben Hare · Accepted Answer · 2016-05-28 15:46:22Z

0

It's printing twice because you have the print inside of the for loop. You should instead increment total inside the for loop and then print it afterwards. If you do:

count = 0
total = 0
for v in "bonbon":
  count += 1
  if v == 'e' or v == 'o' or v == 'u' or v == 'a':
    total += 1

print('the number of vowel in your word is ' + str(total))

It should work.

answered May 28, 2016 at 15:46

Ben Hare

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3 Comments

Tonechas Over a year ago

I would suggest to check wheter a letter is a vowel or not in a more pythonic way, namely if v in 'aeiouAEIOU':

Herc01 Over a year ago

Thank you so much.Its sorted now

Herc01 Over a year ago

Just don't know how to do it/ dont really use this site

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