I want to check a string and if it has no <br /> starting then I don't wanna do any thing
for example mysqtinr = 23435-acs
as you can see no <br /> starting
but if the string has the following then I wanna parse it out
myString = <br /> some text goes here <b> Some other things </b>: just more test <b> http://website/index.php </b> on line <b> 43 </b> <br /> 1234-acd
I want to parse out everything after the last <br />
how can I do that thanks
var index = myString.lastIndexOf("<br />");
if(index > 0)
myString = myString.substring(index + "<br />".length);
br tag<br/> your method won't find it.<br /> specifically. But the example can easily be expanded to support other tags/tag representaions like <br>, <br/> or < br >.substr and indexOf is only setting him up for future headaches.var myregexp = /<br\s*\/>((?:(?!<br\s*\/>).)*)$/;
var match = myregexp.exec(subject);
if (match != null) {
result = match[1];
} else {
result = "";
}
Explanation:
<br\s*/> # match <br /> with optional space
( # capture the following:
(?: # repeat the following, but don't capture (because the outer parens do so already)
(?!<br\s*/>) # assert that it's impossible to match <br />
. # if so, match any character
)* # do this as many times as necessary...
) # (end of capturing group)
$ # ...until the end of the string.
So we first try to match <br/> or <br /> etc. If that fails, the match fails. If not, then we capture every following character until the end of the string unless it's possible to match another <br/> along the way. This ensures that we are indeed matching from the last <br/> onwards. The result will be in backreference nr. 1 (which may be empty if there is nothing after the last <br/>).
