Access line by line to a numpy structured array

Question

I am trying to access to a structured array line by line by iterating on the values of one field of it but even if the value iterate well, the slice of the array doesn't change. Here is my SWE :

import numpy as np
dt=np.dtype([('name',np.unicode,80),('x',np.float),('y',np.float)])
a=np.array( [('a',0.,0.),('b',0.,0.),('c',0.,0.) ],dtype=dt)
for n in a['name']:
  print n,a['name'==n]

gives me :

a (u'a', 0.0, 0.0)
b (u'a', 0.0, 0.0)
c (u'a', 0.0, 0.0)

At each iteration, I always have the same slice of the array... strange ?

Christian K. · Accepted Answer · 2016-04-18 13:00:55Z

4

The last line is not right. The array index evaluates to True or False rather than doing a lookup of a named column. Try this:

for n in a['name']:
    print n,a[a['name']==n]

answered Apr 18, 2016 at 13:00

Christian K.

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3 Comments

Sigmun Over a year ago

The problem is, like I post in another thread, I cannot modify the array that way stackoverflow.com/questions/36693399/…

Christian K. Over a year ago

What kind of modification do you need to do in addition to what you found out yourself in the other post?

Sigmun Over a year ago

Don't worry, it was something wrong in the given answer.

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