create a method that check different object if null throw exception

Question

Let's say we have following code:

public void a(String a) {
   if (a == null) {
      throw new IllegalArgumentException();
   }
}

public void b(Queue<Integer> b) {
   if (b == null) {
      throw new IllegalArgumentException();
   }
}

public void c(Stack<Integer> c) {
   if (c == null) {
      throw new IllegalArgumentException();
   }
}

Is it possible to write a method that do the throw new exception job ? That is something like this:

public void a(String a) {
   check(a);
}

public void b(Queue<Integer> b) {
   check(b);
}

public void c(Stack<Integer> c) {
   check(c);
}

Notice that their types of parameter is not the same.

void check(Object o) { if (o == null) { throw new IllegalArgumentException(); } } ? — ROMANIA_engineer
– ROMANIA_engineer, Commented Apr 10, 2016 at 20:42

Andy Turner · Accepted Answer · 2016-04-10 20:46:10Z

1

you can be more generic like:

public void check(Object a) {
   if (a == null) {
      throw new IllegalArgumentException();
   }
}

edited Apr 10, 2016 at 20:46

Andy Turner

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answered Apr 10, 2016 at 20:42

ΦXocę 웃 Пepeúpa ツ

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1 Comment

Andy Turner Over a year ago

This is perfectly adequate; but note how Guava's Preconditions.checkNotNull is implemented with generics, to allow you to write something like this.a = check(a);.

Jobin John · Accepted Answer · 2021-10-20 06:03:06Z

0

public static <X extends Throwable, T> T ifNullThrow(final T value, @NonNull final Supplier<? extends X> exceptionSupplier)
        throws X {
    if (value != null) {
        return value;
    }
    throw exceptionSupplier.get();
}

answered Oct 20, 2021 at 6:03

Jobin John

311 bronze badge

1 Comment

Community Over a year ago

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