I want to combine adjacent strings to a single 'raw' string in Python, e.g.
>>> s = (
... r"foo\tbar\n"
... "baz\tqux\n")
However this only makes the first part 'raw':
>>> print(s)
foo\tbar\nbaz qux
>>>
Can I somehow propagate the 'r' to all adjacent literals?
The r prefix is part of the literal notation, not part of the resulting string object.
Use it on each line, there is no shortcut here:
s = (
r"foo\tbar\n"
r"baz\tqux\n")
If you really have a lot of these and find all those r prefixes that cumbersome, you could use a raw multiline string (triple quoting) and remove the newlines:
s = ''.join(r"""
foo\tbar\n
baz\tqux\n
""".splitlines())
Note that this won't remove initial whitespace, so you'd either have to start each line at column 0 or use textwrap.dedent() to remove consistent leading whitespace for you:
from textwrap import dedent
s = ''.join(dedent(r"""
foo\tbar\n
baz\tqux\n
""").splitlines())
Quick demo:
>>> s = (
... r"foo\tbar\n"
... r"baz\tqux\n")
>>> s
'foo\\tbar\\nbaz\\tqux\\n'
>>> s = ''.join(r"""
... foo\tbar\n
... baz\tqux\n
... """.splitlines())
>>> s
'foo\\tbar\\nbaz\\tqux\\n'
>>> from textwrap import dedent
>>> s = ''.join(dedent(r"""
... foo\tbar\n
... baz\tqux\n
... """).splitlines())
>>> s
'foo\\tbar\\nbaz\\tqux\\n'
