A better php array_merge [duplicate]

Question

I am looking to do this a better way without the need to hardcode the integers for $justPrices[$i]:

$pricesResult = array_merge($justPrices[0], $justPrices[1], $justPrices[2], $justPrices[3]);

$justPrices is a multidimensional array, containing 4 'bands' of prices within each array. The data for $justPrices being for example:

Array ( [0] => Array ( [0] => 40.95 [1] => 39.95 [2] => 39.45 [3] => 38.95 ) [1] => Array ( [0] => 45.80 [1] => 41.80 [2] => 41.50 [3] => 41.40 ) [2] => Array ( [0] => 45.95 [1] => 42.95 [2] => 41.95 [3] => 41.45 ) [3] => Array ( [0] => 50.00 [1] => 50.00 [2] => 50.00 [3] => 50.00 ) )

The issue is that the amount of arrays within $justPrices will vary from at least 2 to 10+. So I need a way for the parameters for the array_merge() function to vary dependent on the amount of arrays within $justPrices. I was going to use this simple method to get the amount of arrays within $justPrices:

$justPricesMax = count($justPrices);

I could write a for loop, and I might still, I just wondered if there was a better method for what seems on the surface relatively simple!

@Gumbo a single array containing all the prices. I am using that for an average price thing afterwards. — freeMagee
– freeMagee, Commented Sep 3, 2010 at 10:26

Gumbo · Accepted Answer · 2010-09-03 10:12:11Z

11

If you just want to flatten the array, you can use call_user_func_array to call array_merge with the elements of $justPrices as parameters:

$flat = call_user_func_array('array_merge', $justPrices);

This is equivalent to a the function call:

$flat = array_merge($justPrices[0], $justPrices[1], … , $justPrices[count($justPrices)-1]);

edited Sep 3, 2010 at 10:12

answered Sep 3, 2010 at 10:06

Gumbo

657k112 gold badges792 silver badges852 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

A better php array_merge [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related