I have a bash file:
agro_233_720
Inside this bash script I would like to use as variables the part's of it's name that underscore delimitates:
name= agro
ip= 233
resolution= 720
How can I get them ?
I tried to write:
name=`basename "$0"`
but it outputs the hole name (agro_233_720)
Thank you!
With read :
$ IFS='_' read name ip resolution <<< "agro_233_720"
$ printf 'name: %s\nip: %s\nresolution: %s\n' "$name" "$ip" "$resolution"
name: agro
ip: 233
resolution: 720
It splits the string on the IFS delimiter and assign values to vars.
name=$(basename $0 | cut -d_ -f1)
ip=$(basename $0 | cut -d_ -f2)
resolution=$(basename $0 | cut -d_ -f3)
cut splits its input around the delimiter provided with -d and returns the field at the index specified by -f.
See SLePort's answer for a more efficient solution extracting the 3 variables at once without the use of external programs.
With Tcl it can be written as follows,
lassign [ split $argv0 _] name ip resolution
If your Tcl's version is less than 8.5, then use lindex to extract the information.
set input [split $argv0 _]
set name [lindex $input 0]
set ip [lindex $input 1]
set resolution [lindex $input 2]
The variable argv0 will have the script name in it.
