I have a jquery script that loads on document ready and I want to display a hidden popup if a user has already clicked a button (button field). But the condition I check is with php code.
<script>
$( document ).ready(function() {
if (<?php $user_fields->field_button['und'][0]['value'] = 1 ?>) {
var popup = document.getElementById("testpopup1").style.visibility = "visible";
alert("x");
}
});
</script>
But this way doesn't work. Is there a way to put the php code inside the if statement of my jquery code or I have to try something else?