Python EOF error when reading input

Question

n = input()
dum = input()
d = {}
for i in range(0,n+1):
    x = raw_input()
    x = x.split(" ")
    d[int(x[0])] = int(x[1])

array = d.keys()

for key in d.keys():
    if(d[key]!=0):
        if(d[key] not in d.keys()):
            for i in d.keys():
                for j in d.keys():
                    if(i!=j and i!=key and j!=key):
                        if(i+j==d[key]):
                            # print str(i)+"-"+str(j)
                            if(i in array):

                                array.remove(i)
                            if(j in array):
                                # print j
                                array.remove(j)
        else:
            # print d[key]
            array.remove(d[key])
print array[0]

When I execute this Python code I am getting "EOF error when reading input".

Can you please help? I am running Python 2.7.5

Error Traceback

Traceback (most recent call last):
File "prog.py", line 1, in <module>
EOFError: EOF when reading a line

If array is empty, you would get that. But I am unable to execute the code because of EOF error. — Mark
– Mark, Commented Feb 27, 2016 at 10:25

Forge · Accepted Answer · 2016-02-27 11:03:51Z

4

I can't seem to reproduce this error although using the same input as you did. Maybe you have a newline character before the input you have specified?
Try running this code using python prog.py in your terminal.

EOF error is expected if no data is given when calling input or raw_input as explained in the documentation.

Also, it's advisable to use raw_input and not input when getting input from the user on python 2, it's not going to fix your error though.

answered Feb 27, 2016 at 11:03

Forge

6,8727 gold badges49 silver badges65 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Hossain Muctadir · Accepted Answer · 2016-02-27 14:18:39Z

2

In Python 2, raw_input() returns a string, and input() tries to run the input as a Python expression. So, changing your first line to something like this should work.

n = int(raw_input())

According to the official documentation

Equivalent to eval(raw_input(prompt)).

This function does not catch user errors. If the input is not syntactically valid, a SyntaxError will be raised. Other exceptions may be raised if there is an error during evaluation.

edited Feb 27, 2016 at 14:18

answered Feb 27, 2016 at 14:11

Hossain Muctadir

3,6361 gold badge21 silver badges33 bronze badges

Comments

jonatan · Accepted Answer · 2016-02-27 14:59:55Z

0

This:

for i in range(0,n+1):

does n+1 number of iterations, yet your input file:

Only has n number of lines remaining when that loop is about to start. Upon attempting to read a n+1th line, you'll get an EOFError as there are no more lines.

answered Feb 27, 2016 at 14:59

jonatan

1351 silver badge7 bronze badges

Comments

Benjamin Lowry · Accepted Answer · 2018-03-21 13:29:20Z

0

I was really confused by this problem as well, and I couldn't find the direct answer on other resources.

However, what the issue was for me was I am using PyCharm and my configurations for my .py file were wrong. Basically, I had it looking for an external file to source input from instead of the console.

I had to change these configurations by unchecking the "emulate terminal in output console" box in the picture below and then it worked perfectly.

answered Mar 21, 2018 at 13:29

Benjamin Lowry

3,8491 gold badge26 silver badges29 bronze badges

Collectives™ on Stack Overflow

Python EOF error when reading input

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related