Php variable increment

Question

So i have the following code that works and outputs the information let's say 2 11. I would like to have $keyidcall increment in variable name so $keyidcall2, $keyidcall3....... with the additional variables I would like the variable to hold the correct value so I can call it later. so expected output would be $Apiammount ="2"; echo $keyidcall; would echo 2 echo $keyidcall: would echo 11

while($Apiammount > 1){
    $Keyidquery = mysqli_query($connection, "SELECT ID FROM `Characterapi` WHERE UserId = '$Idcall'");
    while($keyid = mysqli_fetch_assoc($Keyidquery)){
        $keyidcall = $keyid['ID'];
        echo $keyidcall;
    }

    $Apiammount--;
}

Any time you find yourself using numbered variables like that, you almost always should use an array instead. — Barmar
– Barmar, Commented Feb 19, 2016 at 22:02
Looking at your code, the $Keyidquery will be the same all the time, since '$Idcall' is not changed anywhere in the loop. If you want to return the same value and store it in multiple variables there is no need to run the query over and over again. Once you got that sorted, as @Adam Copley suggested, store them in array. — Emil Borconi
– Emil Borconi, Commented Feb 19, 2016 at 22:07

Adam Copley · Accepted Answer · 2016-02-19 21:54:18Z

1

The better way to do this would be to store the values in an array.

$keyidcall[] = $keyid['ID'];

Then you can refer to them later as

echo $keyidcall[0]; echo $keyidcall[1];

in the order that they were entered in.

Or if you wanted something more specific to refer to it by, you could use

$keyidcall[$Apiammount] = $keyid['ID'];

then you would refer to them as:

echo $keyidcall[<apiamount>];

Assuming you know what that would be.

answered Feb 19, 2016 at 21:54

Adam Copley

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3 Comments

Grasume Over a year ago

So after realiising i needed to create the array this worked AMAYAZINGLY. TY

Grasume Over a year ago

now is there a way i can use the $keyidcall[] in a msqli query where i can do upon $keyidcall[0] = 3 in a my msqli query the call uses the three and i can loop it ?

Adam Copley Over a year ago

I recommend you post a separate question and link in these comments. What your asking needs a little more detail

jhaagsma · Accepted Answer · 2016-02-19 21:59:49Z

0

You can do:

$i = 0;
while($foo){
  $name = 'keyidcall';
  $i++;
  $newvar = $name . $i;
  echo $$newvar;
}

And $$newvar will echo the value of "keyidcallX" where X is an incrementing value. Not sure if that's what you meant.

answered Feb 19, 2016 at 21:59

jhaagsma

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