How to pass interface instance in class constructor in php

Question

I have the following class

class InterfaceImplementation{
    public function __construct(ServiceInterface $oService){
        $this->oService = $oService;
    }
}

When I create the class object

$obj = new InterfaceImplementation();

How to pass the interface instance?And is this the correct way to code?

I was stumbled upon this question ytd too, I think it means to pass an object that implement that specific interface instead of passing the literal interface itself — Andrew
– Andrew, Commented Feb 9, 2016 at 3:47

Sebastian Malaca · Accepted Answer · 2016-02-09 20:35:46Z

2

Any object that will implement ServiceInterface can be used and pass to the constructor. You have to create an instance of the class, but in InterfaceImplementation you will use the interface API (methods declarated in the interface), not the methods from the particular class.

answered Feb 9, 2016 at 20:35

Sebastian Malaca

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Comments

Swaraj Giri · Accepted Answer · 2016-02-09 04:00:58Z

0

Before you can create a new InterfaceImplementation, you need to have a valid ServiceInterface object. Once you have the service object you can pass it while creating InterfaceImplementation

$service = new ServiceInterface(); // make sure its a valid object
$implementation = new InterfaceImplementation($service);

Pro tip: Look up a dependency injection container. It will make your life so much easier.

answered Feb 9, 2016 at 4:00

Swaraj Giri

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