Iterating nested json in python

Question

I have JSON in this format. How can I print each value and go inside the objects. Also, the json can vary and also the name, so I need a generic solution.

output = {'name':'StackOverflow',
       'competitors':[{   'competitor':'bing',
                          'link':'bing.com'},
                      {   'competitor':'google',
                          'link':'google.com'}],
       'acquisition': {'acquired_day': 16,
                       'acquired_month': 12,
                       'acquired_year': 2013,
                       'acquiring_company': {'name': 'Viggle',
                                             'permalink': 'viggle'}}}

To clarify: you already have a dictionary, and you want to print all the values, including values in nested dictionaries, but not the keys? What is the expected output for your example? — timgeb
– timgeb, Commented Feb 8, 2016 at 6:18
I need to iterate through each key and value, replace all the values in the json with some other value. — user1733735
– user1733735, Commented Feb 8, 2016 at 6:22
You have to traverse over each key and value of your dict. Also have to check, if value is again dict, then do same. — NPatel
– NPatel, Commented Feb 8, 2016 at 6:22
One last try before I decide this is a waste of time: show the expected result. — timgeb
– timgeb, Commented Feb 8, 2016 at 6:24

Zack Graber · Accepted Answer · 2016-02-08 06:53:36Z

1

You can use isinstance to check if something is a dict or a list. Something like this may work, but I haven't checked it.

output = {'name': 'StackOverflow',
      'competitors': [{'competitor': 'bing',
                       'link': 'bing.com'},
                      {'competitor': 'google',
                       'link': 'google.com'}],
      'acquisition': {'acquired_day': 16,
                      'acquired_month': 12,
                      'acquired_year': 2013,
                      'acquiring_company': {'name': 'Viggle',
                                            'permalink': 'viggle'}}}


def traverse(obj):
    if isinstance(obj, dict):
        for key, value in obj.iteritems():
            print('dict_key', key)
            traverse(value)
    elif isinstance(obj, list):
        for value in obj:
            traverse(value)
    else:
        print('value', obj)


traverse(output)

answered Feb 8, 2016 at 6:53

Zack Graber

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1 Comment

user1733735 Over a year ago

This works for the value but I would need keys as well as I would need to set that value with a new value

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